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3 years ago

He had to wait 1 hour and 45 minutes at the airport in San Francisco. Then Frank

Mathematics

1 answer:

FinnZ [79.3K]3 years ago

4 0

Answer:

Step-by-step explanation:

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What is 1/2+1/4+20.00?

dimulka [17.4K]

0.5 + 0.25 + 20.00 = 20.75

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3 years ago

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What is the solution to the equation P over 9= 72?

Fed [463]

P / 9 = 72

Multiply both sidess by 9

P / 9 (9) = 72 (9)

p = 648

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3 years ago

A math tutor charges $30 per session each month plus a $5 scheduling fee. If jane pays a total of $215 in May for tutoring devic

wel

Answer:

it should be 6 not 100% sure though

Step-by-step explanation:

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3 years ago

You want to get from a point A on the straight shore of the beach to a buoy which is 54 meters out in the water from a point B o

anyanavicka [17]

Answer:

$x =\dfrac{45 \sqrt{6}}{ 2}$

Step-by-step explanation:

From the given information:

The diagrammatic interpretation of what the question is all about can be seen in the diagram attached below.

Now, let V(x) be the time needed for the runner to reach the buoy;

∴ We can say that,

$\mathtt{V(x) = \dfrac{70-x}{7}+\dfrac{\sqrt{54^2+x^2}}{5}}$

In order to estimate the point along the shore, x meters from B, the runner should stop running and start swimming if he want to reach the buoy in the least time possible, then we need to differentiate the function of V(x) and relate it to zero.

i.e

The differential of V(x) = V'(x) =0

= $\dfrac{d}{dx}\begin {bmatrix} \dfrac{70-x}{7} + \dfrac{\sqrt{54^2+x^2}}{5} \end {bmatrix}= 0$

$-\dfrac{1}{7}+ \dfrac{1}{5}\times \dfrac{x}{\sqrt{54^2+x^2}}=0$

$\dfrac{1}{5}\times \dfrac{x}{\sqrt{54^2+x^2}}= \dfrac{1}{7}$

$\dfrac{5x}{\sqrt{54^2+x^2}}= \dfrac{1}{7}$

$\dfrac{x}{\sqrt{54^2+x^2}}= \dfrac{1}{\dfrac{7}{5}}$

$\dfrac{x}{\sqrt{54^2+x^2}}= \dfrac{5}{7}$

squaring both sides; we get

$\dfrac{x^2}{54^2+x^2}= \dfrac{5^2}{7^2}$

$\dfrac{x^2}{54^2+x^2}= \dfrac{25}{49}$

By cross multiplying; we get

$49x^2 = 25(54^2+x^2)$

$49x^2 = 25 \times 54^2+ 25x^2$

$49x^2-25x^2 = 25 \times 54^2$

$24x^2 = 25 \times 54^2$

$x^2 = \dfrac{25 \times 54^2}{24}$

$x =\sqrt{ \dfrac{25 \times 54^2}{24}}$

$x =\dfrac{5 \times 54}{\sqrt{24}}$

$x =\dfrac{270}{\sqrt{4 \times 6}}$

$x =\dfrac{45 \times 6}{ 2 \sqrt{ 6}}$

$x =\dfrac{45 \sqrt{6}}{ 2}$

8 0

3 years ago

3. A rectangular floor of dimensions

ICE Princess25 [194]

Answer:

area of the floor = 540*840.

=453600 cm sq.

area of the marbal piece = 1/2 * 40* 30 = 600 cm sq.

now,

no. of marble piece reqd. = 453600 / 600 = 756 marbal piece.

hope it helps u.

4 0

3 years ago

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