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Annette [7]
2 years ago
5

The endpoints of a

Mathematics
1 answer:
Zolol [24]2 years ago
6 0

Answer:

2nd option

Step-by-step explanation:

the equation of a circle in standard form is

(x - h)² + (y - k)² = r²

where (h, k ) are the coordinates of the centre and r is the radius

the centre is at the midpoint of the endpoints of the diameter.

The coordinates of the centre is the average of the coordinates of the endpoints.

centre = ( \frac{-4+2}{2}, \frac{7-1}{2} ) = (\frac{-2}{2} , \frac{6}{2} ) = (- 1, 3 )

the radius is the distance from the centre to either of the endpoints

using the distance formula to calculate r

r = \sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2

with (x₁, y₁ ) = (- 1, 3 ) and (x₂, y₂ ) = (2, - 1 )

r = \sqrt{(2-(-1))^2+(-1-3)^2}

  = \sqrt{(2+1)^2+(-4)^2}

  = \sqrt{3^2+16}

  = \sqrt{9+16}

  = \sqrt{25}

   = 5

then equation of circle is

(x - (- 1) )² + (y - 3)² = 5² , that is

(x + 1)² + (y - 3)² = 25

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<u>Statement</u><u>:</u>

The circle has a diameter of 16 inches.

<u>To </u><u>find </u><u>out:</u>

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