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Dmitry [639]
2 years ago
9

A wave is modeled with the function y = 1 /2 sin 3 θ , where θ is in radians. Describe the graph of this function, including its

period, amplitude, and points of intersection with the x-axis.
Mathematics
1 answer:
anygoal [31]2 years ago
8 0
Use desmos graphing calculator
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F(x)=3x-6 find f(4) I
Akimi4 [234]
To find f(4), you want to substitute x for 4 in the equation. It would look like:

f(4) = 3(4) - 6

Then, just do the math:

f(4) = 12 - 6
f(4) = 6

Hope this helps! :)
3 0
3 years ago
Describe how the graph of y= x2 can be transformed to the graph of the given equation. y = x2 + 8
ANEK [815]
When you add 8 to the end of a function formula, the graph moves UP 8 units.  This is often called either a translation or vertical shift.

3 0
3 years ago
The principal Po is invested in an account that pays an annual interest rate r (written as a decimal), compounded n times per ye
AVprozaik [17]
At the end of the first year, the correct formula is this one:
P=P_0(1+r)
The second year, we add r times the above amount, we get:
P_0(1+r)+r(P_0(1+r))=P_0(1+2r+r^2)\\=P_0(1+r)^2
Iterating the process, we get the general formula of any number of years:
P=P_0(1+r)^n
6 0
3 years ago
The length of a rectangle is twice it’s width.The length is 12cm.Work out the area of the rectangle
aliina [53]

Answer:


Step-by-step explanation:

As with all word problems we first have to convert it to an equation or equations.

L = length of the Rectangle and W = its width

So L = 2 * W

A = area of the rectangle which is 128 cm^2

So    A = L * W = 128 cm^2

substitute 2W for L from the 1st equation to give    A = 2 * W * W = 2 * W^2 = 128 cm^2

Thus    W^2 = 64 cm^2

finally  W = 8 cm  and therefore  L = 2 * W = 16 cm

The perimeter P = 2 * (L+W) = 2* (8cm + 16cm) = 2 * 24cm = 48 cm

6 0
3 years ago
I have completed everything except for the last box. Can someone please help me on the last box? Thank you for your help!
Lera25 [3.4K]

Answer:

2.5\%

Step-by-step explanation:

From the Empirical Rule, 95% of the data shown falls between 63 and 95. The other 5% is evenly distributed to each side (since the distribution is bell-shaped), hence there being \boxed{2.5\%} of scores less than 63.

The directions say to give the approximate percentage which is vague. You may have to input 3\% if it does not accept 2.5\%.

8 0
3 years ago
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