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Nastasia [14]
3 years ago
6

Which numbers below belong to the solution set of the inequality 9x>117

Mathematics
1 answer:
vlada-n [284]3 years ago
8 0
Given answer choices(?)
A.12
B.6
C.8
D.14
E.13
F. 19

117/9 equals 13, therefore we need numbers greater than 13 to multiply to 9 in order to get a number that is more than 117. Therefore x is numbers greater than 13. Choose all (if given the option) that is above number 13. Exclude all the numbers that are 13 and below. That means A, B, C, and E are not the correct answers nor possible solutions to the inequality. 

Bonus: I'll show you a hint on how you can figure out the products of 9 x 1 - 10. Take all ten of your fingers and hold down the number you want to multiply with 9. Let's say 4. Hold down your forth finger. The numbers before that finger is the tens and the fingers after is your ones. (Note that you don't count that finger that is down. The finger that is down (in this case your fourth) acts as a barrier between the tens and the ones values) Your answer would be 3 fingers in the front (meaning 3 tens) and 6 fingers in the back (meaning 6 ones) Together that's 36. 9 * 4 = 36.


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6 0
3 years ago
Malachi’s garden is 2 3/5 meters long. He wants to plant tomato plants every 1/5 of a meter. How many plants can Malachi fit?
Sophie [7]
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5 0
3 years ago
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The general form of an parabola is 2x2−12x−3y+12=0 .
Murljashka [212]

Answer:

The standard form of the parabola is (x-3)^2=4*\frac{3}{8}(y+2)

Step-by-step explanation:

The standard form of a parabola is

(x-h)^2=4p(y-k).

In order to convert 2x^2-12x-3y+12=0 into the standard form, we first separate the variables:

2x^2-12x+3y+12=0\\\\2x^2-12x+12=3y

we now divided both sides by 2 to remove the coefficient from 2x^2 and get:

x^2-6x+6=\frac{3}{2}y.

We complete the square on the left side by adding 3 to both sides:

x^2-6x+6+3=\frac{3}{2}y+3

x^2-6x+9=\frac{3}{2}y+3

(x-3)^2=\frac{3}{2}y+3

now we bring the right side into the form 4p(y-k) by first multiplying the equation by \frac{2}{3}:

\frac{2}{3} *(x-3)^2=\frac{2}{3} *(\frac{3}{2}y+3)\\\\\frac{2}{3} *(x-3)^2=y+2

and then we multiplying both sides by \frac{3}{2} to get

(x-3)^2=\frac{3}{2} (y+2).

Here we see that

4p=\frac{3}{2}

\therefore p=\frac{3}{8}

Thus, finally we have the equation of the parabola in the standard form:

\boxed{(x-3)^2=4*\frac{3}{8}(y+2)}

5 0
3 years ago
Find the inverse of A(r)=15+3r
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Answer:

A(r)=15-3r

Step-by-step explanation:

8 0
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lbvjy [14]

Answer:

We know that, two quantities are proportional when they vary directly with each other.

i.e. quantities x and y are proportional when they have the relation y = kx, where k is any constant called constant of proportionality.

Since, the quantities are in relation y = kx.

So, for x = 0 we get that the value of y = 0.

As, the point ( 0,0 ) satisfies this relation i.e. it is a solution of y =  kx.

Hence, in proportional relationship, the graph will pass through ( 0,0 ).

7 0
3 years ago
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