2 years ago

Which is the correct option, I’m very confused by this question? sin2x=

1 answer:

3 0

Answer:

The answer is definitely Option A

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Anika [276]

Answer: (110.22, 125.78)

Step-by-step explanation:

The confidence interval for the population mean is given by :-

$\mu\ \pm z_{\alpha/2}\times\dfrac{\sigma}{\sqrt{n}}$

Given : Sample size = 463

$\mu=118\text{ minutes}$

$\sigma=65\text{ minutes}$

Significance level : $\alpha=1-0.99=0.01$

Critical value : $z_{\alpha/2}=z_{0.005}=\pm2.576$

We assume that the population is normally distributed.

Now, the 90% confidence interval for the population mean will be :-

$118\ \pm\ 2.576\times\dfrac{65}{\sqrt{463}} \\\\\approx118\pm7.78=(118-7.78\ ,\ 118+7.78)=(110.22,\ 125.78)$

Hence, 99% confidence interval for the mean study time of all first-year students = (110.22, 125.78)

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3 years ago

PIT_PIT [208]

the answer is m<6=80

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elena55 [62]

Forgive me if this is wrong. I haven't done stat in a year, but comment if you need clarification!

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3 years ago

stiks02 [169]

3 x 1/8 bottom left. The third one

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Phoenix [80]

He does not miss any of the movie

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