Solution
The table below is the required sample space of the to fair die
From the above table
The sample space contain 36 outcomes
Event A: The sum is greater than 9
we will look at the table and count all the elements that are greater than 9
There are 6 elements (they are 10, 10, 10, 11, 11, 12 from the table)
The probability for event A will be
P(A) = 1/6
Event B: The sum is an even number.
We will look at the table and count the number of elements that are even
There are 18 elements (notice that there are 3 even number on each of the 6 rows of the table)
The probability for event B will be
p(B) = 1/2
cos 0 = 1/6
1 - cos²0 = sin²0
sin²0 = 35/36
in quadrant IV (4) the cos is positive sin is negative.
sin0 = - √35/6
Answer:
Neon= -10+10= 0 on no change
oxide=-10+8=-2
copper=-27 +29 = 2
tin= -50 +50 = 0 or no change
Step-by-step explanation:
Its basically subtraction ( i pretty sure thats right)
Step-by-step explanation:
I would suggest that this is cluster sampling.
The teacher is selecting a cluster of the population at random to sample.
This is a method of probabalistic sampling.
Answer:
B and D
Step-by-step explanation:
Geometric sequences and series. A geometric sequence is a sequence of numbers that follows a pattern were the next term is found by multiplying by a constant called the common ratio, r.
an = ar^(n-1)
d) 1/3, 2/3, 4/3, 8/3, 16/3, . . . .
1/3 * 2 = 2/3
2/3 * 2 = 4/3
4/3 * 2 = 8/3
where r = 2, constant multiplier is 2. //Answer
b) 320, 80, 20, 5, 1.25, . . . . .
320 * 1/4 = 80
80 * 1/4 = 20
20 * 1/4 = 5
r = 1/4 //Answer
Answer: B and D
//Hope this helps.
