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2 years ago

Tabular representations for the functions f, g, and h are given below. Write g(x) and h(x) as transformations of f(x).

Mathematics

2 answers:

Maurinko [17]2 years ago

7 0

9514 1404 393

Answer:

g(x) = f(x -1)

h(x) = f(x) +4

Step-by-step explanation:

We notice that the output values correspond to the output values of f(x), but the input to f(x) is 1 less than the corresponding input to g(x). For some given value of x, ...

g(x) = f(x -1)

The input values correspond to those for f(x), but the output values are all 4 more than for f(x).

h(x) = f(x) +4

Leto [7]2 years ago

4 0

Answer:

the answer for g is -3 that is all I know

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Karlie has a collection of quarters, dimes, and nickels that equal $2.70. If she has 7 quarters and 7 nickels, how many dimes do

iogann1982 [59]

Answer:

22 Dimes

Step-by-step explanation:

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3 years ago

For the function y=3x2: (a) Find the average rate of change of y with respect to x over the interval [3,6]. (b) Find the instant

nirvana33 [79]

Answer:

The instantaneous rate of change of $y$ with respect to $x$ at the value $x = 3$ is 18.

Step-by-step explanation:

a) Geometrically speaking, the average rate of change of $y$ with respect to $x$ over the interval by definition of secant line:

$r = \frac{y(b) -y(a)}{b-a}$ (1)

Where:

$a$ , $b$ - Lower and upper bounds of the interval.

$y(a)$ , $y(b)$ - Function exaluated at lower and upper bounds of the interval.

If we know that $y = 3\cdot x^{2}$ , $a = 3$ and $b = 6$ , then the average rate of change of $y$ with respect to $x$ over the interval is:

$r = \frac{3\cdot (6)^{2}-3\cdot (3)^{2}}{6-3}$

$r = 27$

The average rate of change of $y$ with respect to $x$ over the interval $[3,6]$ is 27.

b) The instantaneous rate of change can be determined by the following definition:

$y' = \lim_{h \to 0}\frac{y(x+h)-y(x)}{h}$ (2)

Where:

$h$ - Change rate.

$y(x)$ , $y(x+h)$ - Function evaluated at $x$ and $x+h$ .

If we know that $x = 3$ and $y = 3\cdot x^{2}$ , then the instantaneous rate of change of $y$ with respect to $x$ is:

$y' = \lim_{h \to 0} \frac{3\cdot (x+h)^{2}-3\cdot x^{2}}{h}$

$y' = 3\cdot \lim_{h \to 0} \frac{(x+h)^{2}-x^{2}}{h}$

$y' = 3\cdot \lim_{h \to 0} \frac{2\cdot h\cdot x +h^{2}}{h}$

$y' = 6\cdot \lim_{h \to 0} x +3\cdot \lim_{h \to 0} h$

$y' = 6\cdot x$

$y' = 6\cdot (3)$

$y' = 18$

The instantaneous rate of change of $y$ with respect to $x$ at the value $x = 3$ is 18.

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3 years ago

What is the answer to the problem (m-3)(-10)

OverLord2011 [107]

The answer is -10m + 30

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3 years ago

How to find the θ in this equation: tan(θ+16°)=1/tan(θ+60°) by using the trigonometric identities?thanks

DedPeter [7]

Answer:

$\huge \theta =7°$

Step-by-step explanation:

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3 years ago

The ratio of a to b is 9:2, and the ratio of c to b is 5:3. What is the ratio of a to c?

xz_007 [3.2K]

The answer is that the ratio of a to c is 9/5

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3 years ago