The solutions for the given equation
are x = -1 and x = 3/4. Using the quadratic formula, the solutions for the given equation are calculated.
<h3>What is the quadratic formula?</h3>
The formula which is used to calculate the roots(solutions) of the quadratic equation in the form
is
x = [- b ±
]/2a
<h3>Calculation:</h3>
The given equation is 
In comparison with the standard form of quadratic equation
,
we get, a = 4, b = 1 and c = -3
So, solving the given equation using the quadratic formula,
x = [- b ±
]/2a
= [- 1 ±
]/2(4)
= [-1 ±
]/8
= (-1 ± 7)/8
Thus, x = (-1 + 7)/8 = 3/4 and x = (-1-7)/8 = -8/8 = -1
Therefore, the solutions of the given equation are x = -1 and x = 3/4.
Learn more about solving quadratic equations here:
brainly.com/question/1214333
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Should be 0 if this is exponents
let number of green balls= x
let number of orange balls=x+4
x+x+4=38
2x=38-4
2x=34
x=17
number of green balls=17
number of orange balls=21
Answer:
(6,26)
Step-by-step explanation:
You will take the points and graph them since these are both positive equations they will go up and to the right.
both intersect at (6,26)
also if you forgot how to graph it, I got you
1. find the rate of change (as I will call it) THIS IS YOUR NUMBER NEXT TO THE X!!! this means that the line will go up 4 and over 1 then your whole number, in this example would be 2 is your y-intersect (the place on the y-axis where the line passes) after that you should be able to draw your lines and find the poi!
Please comment if I got something wrong! I don't want to be giving bad advice
Answer: See below.
The sine ratio is the ratio of the opposite side over the hypotenuse in a right triangle. The hypotenuse is always the largest side of a triangle.
Therefore, the denominator will always be the largest. If the denominator is larger than the numerator, it will be a number less than one.
And it will be positive because it is an acute angle so the triangle when plotting in the unit circle would only be in the first quadrant. All values in the first quadrant are positive.