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Sergeeva-Olga [200]
4 years ago
12

Which expressions are not polynomials?

Mathematics
1 answer:
Naddika [18.5K]4 years ago
8 0

Answer:

The middle two expressions shown are not polynomials

Step-by-step explanation:

Polynomial terms have positive integer exponents on any variables. A 2/3 power is not an integer exponent. Division by y is equivalent to an exponent of -1, which is not a positive integer.

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Draw two identical rectangle. Shade 1 seventh of one rectangle and 1 tenth of the other. Lavel the unit fractions. Use you recta
Bumek [7]

Answer:

1/7 is greater than 1/10 using coordinates and its area of the division concept.

Step-by-step explanation:

We have to draw two identical rectangles and have to shade them.

Here is the diagram attached with.<em> (With some approximation)</em>

We can see that \frac{1}{7} > \frac{1}{10} .

Rectangles are identical.

When we look upon \frac{1}{10} it can be observed that each division on the coordinate plane have 2 boxes only...

Where as \frac{1}{7} fraction consists more than 2 boxes ..

So we can say that the area covered for each division in \frac{1}{7} is more than that of \frac{1}{10} .

Mathematical concept:

If the numerator are same then to compare fractions we look upon denominators values.

Greater the denominator lesser is the fraction values.

So,

Finally we can say that 1/7 is greater than 1/10 .

5 0
3 years ago
A bakery sold 275 mocha cupcakes in a day, which was 55% of the total number of
Morgarella [4.7K]

Answer:

151 cupcakes

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Chance can wash the car in 2 hours, while Sandy can wash the same car in 4 hours. How many hours would it take for them to wash
san4es73 [151]
<span>1 hour and 1/3rd of an hour.</span>
6 0
3 years ago
Suppose theta= 11pi/12. How do you use the sum identity to find the exact value of sin theta?
SIZIF [17.4K]
The better way is, first we have to find the equivalent in degrees

2\pi=360\º

\frac{11\pi}{12}=345\º

now we can change this value to -15\º

how do we get an angle like this?!

30\º-45\º=-15\º

then

sin(30\º-45\º)=sin(30\º)*cos(45\º)-sin(45\º)*cos(30\º)

\begin{Bmatrix}sin(30\º)&=&\frac{1}{2}\\\\sin(45\º)&=&cos(45\º)&=&\frac{\sqrt{2}}{2}}\end{matrix}\\\\cos(30\º)&=&\frac{\sqrt{3}}{2}\end{matrix}

now we replace this values

sin(-15\º)=\frac{1}{2}*\frac{\sqrt{2}}{2}-\frac{\sqrt{2}}{2}*\frac{\sqrt{3}}{2}

sin(-15\º)=\frac{\sqrt{2}}{4}-\frac{\sqrt{6}}{4}

\boxed{\boxed{sin(-15\º)=sin(345\º)=\frac{\sqrt{2}-\sqrt{6}}{4}}}
4 0
3 years ago
Let f(x) = 1/x. Find a number b so that the average rate of change of f on the interval
Bezzdna [24]

Answer:

huh try multiplying

Step-by-step explanation:

6 0
4 years ago
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