The length of a rectangular floor is two ft more than its width. If the area of the floor is 63 ft, find the length and the widt
1 answer:
Answer:
width = 7 and length = 9
Step-by-step explanation:
Let's assume width = w, and length = 2 + w
So area of a rectangle = width * length
63 ft² = w (2 + w)
63 = 2w + w²
w² + 2w - 63 = 0
Use the quadratic formula to solve this
here, a = 1, b = 2 and c = -63
w = 7 or -9
The dimensions of a rectangle cannot be negative. So we take the dimension, w = 7.
Width = 7 and Length = 7+2 = 9
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Answer:
Step-by-step explanation:
a). Since, ΔABC ~ ΔWYZ
Their corresponding sides will be proportional.
--------(1)
By applying Pythagoras theorem in ΔABC,
AB² = AC² + BC²
BC² = AB² - AC²
BC² = (194)² - (130)²
BC² = 20736
BC = 144
From equation (1)
WY =
WY = = 1.35
WZ =
WZ = = 0.90
b). tan(A) =
=
=
Since, ΔABC ~ ΔWYZ,
∠A ≅ ∠W
Therefore, tangent of angle A and angle W will measure .