8.8 million is the right answer
The range is the number of units between the smallest and largest number. organising your numbers from smallest to largest:
12, 19, 20, 28, 34, 36, 45, 45
in your case 12 is the smallest number of your set. lowering it to 3 would increase the distance between the two numbers, therefore increasing the range
hope that helps :)
The cardinality of the union between two sets is given by

In fact, if an element is in both A and B, it is counted in both N(A) and N(B), so we're counting it twice. By subtracting the cardinality of the interserction, we're taking back one of these "extra-counted" element, and the count is correct. In your case, the numbers are

This means that the two sets cover, without repetitions, 43 of the 66 elements in the sets. So, there are

elements which are in neither A nor B
Let
x--------> the length side of the rectangle
y--------> the width side of the rectangle
we know that
The perimeter of a rectangle is equal to



Substitute the values of x and y in the formula of perimeter
![P=2*[(4a + 96)/(a + 15)]+2*[(4a + 24)/(a + 15)]](https://tex.z-dn.net/?f=%20P%3D2%2A%5B%284a%20%2B%2096%29%2F%28a%20%2B%2015%29%5D%2B2%2A%5B%284a%20%2B%2024%29%2F%28a%20%2B%2015%29%5D%20)
![P=[(8a + 192)/(a + 15)]+[(8a + 48)/(a + 15)]](https://tex.z-dn.net/?f=%20P%3D%5B%288a%20%2B%20192%29%2F%28a%20%2B%2015%29%5D%2B%5B%288a%20%2B%2048%29%2F%28a%20%2B%2015%29%5D%20)
![P=[(16a + 240)/(a + 15)]](https://tex.z-dn.net/?f=%20P%3D%5B%2816a%20%2B%20240%29%2F%28a%20%2B%2015%29%5D%20)
![P=16*[(a + 15)/(a + 15)]](https://tex.z-dn.net/?f=%20P%3D16%2A%5B%28a%20%2B%2015%29%2F%28a%20%2B%2015%29%5D%20)

therefore
<u>the answer part a) is </u>
the total length of fencing material required would be 
Part b) Divide the perimeter by the width of the prebuilt fence sections
so

therefore
<u>the answer Part b) is </u>

What are we supposed to be doing