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Margaret [11]
2 years ago
11

Which fraction has the greatest value? A number line going from negative 1 to positive 1 in increments of 1. StartFraction 5 Ove

r 6 EndFraction StartFraction 1 Over 6 EndFraction Negative StartFraction 1 Over 6 EndFraction Negative StartFraction 5 Over 6 EndFraction
Mathematics
2 answers:
frosja888 [35]2 years ago
8 0

Fractions are numbers that are represented by the quotients of two integers

The fraction with the greatest value is 5/6

<h3>How to determine the greatest fraction</h3>

The fractions are given as:

1/6, 5/6, -1/6 and -5/6

Negative numbers are less than positive numbers.

So, the remaining fractions are:

1/6 and 5/6

Both fractions have the same denominator.

So, we consider the numerator

5 is greater than 1

Hence, the fraction with the greatest value is 5/6

Read more about fractions at:

brainly.com/question/11562149

GuDViN [60]2 years ago
4 0

Answer:

C

Step-by-step explanation:

i got it right

plz mark me as brainly!

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3 years ago
Thompson and Thompson is a steel bolts manufacturing company. Their current steel bolts have a mean diameter of 144 millimeters,
valentinak56 [21]

Answer:

The probability that the sample mean would differ from the population mean by more than 2.6 mm is 0.0043.

Step-by-step explanation:

According to the Central Limit Theorem if we have a population with mean μ and standard deviation σ and appropriately huge random samples (n > 30) are selected from the population with replacement, then the distribution of the sample  means will be approximately normally distributed.

Then, the mean of the distribution of sample mean is given by,

\mu_{\bar x}=\mu

And the standard deviation of the distribution of sample mean  is given by,

\sigma_{\bar x}=\frac{\sigma}{\sqrt{n}}

The information provided is:

<em>μ</em> = 144 mm

<em>σ</em> = 7 mm

<em>n</em> = 50.

Since <em>n</em> = 50 > 30, the Central limit theorem can be applied to approximate the sampling distribution of sample mean.

\bar X\sim N(\mu_{\bar x}=144, \sigma_{\bar x}^{2}=0.98)

Compute the probability that the sample mean would differ from the population mean by more than 2.6 mm as follows:

P(\bar X-\mu_{\bar x}>2.6)=P(\frac{\bar X-\mu_{\bar x}}{\sigma_{\bar x}} >\frac{2.6}{\sqrt{0.98}})

                           =P(Z>2.63)\\=1-P(Z

*Use a <em>z</em>-table for the probability.

Thus, the probability that the sample mean would differ from the population mean by more than 2.6 mm is 0.0043.

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Nat2105 [25]

Answer:4 to 3

Step-by-step explanation:

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Answer:

Since a fraction represents a division, we should do that division to know what the value of a fraction is. The larger numerator, the larger the value of the fraction will be; and the larger denominator, the smaller the fraction will be. ...

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