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Ymorist [56]
2 years ago
10

Which shows the solution set to the

Mathematics
1 answer:
Paha777 [63]2 years ago
5 0

Answer:

The answer is C hope this can help you out!

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Pls pls help<br> Show work :)
Natasha2012 [34]

9514 1404 393

Answer:

  31.243 units

Step-by-step explanation:

The mnemonic SOH CAH TOA reminds you of the relationships between sides and angles in a right triangle. Using the attached figure, it is convenient to find the length of BE as an intermediate step in the solution.

  Sin = Opposite/Hypotenuse

  sin(30°) = BE/100

  BE = 100·sin(30°)

Then ...

  Tan = Opposite/Adjacent

  tan(58°) = BE/x

  x = BE/tan(58°) = 100·sin(30°)/tan(58°)

  x ≈ 31.243 . . . . units

_____

<em>Comment on the figure</em>

The intermediate problem in creating the figure was to locate point D. That was accomplished by locating point C on a line at an angle of 58° CCW from the horizontal, using point B as a center. Then D is the intersection of BC with the x-axis. BE is drawn perpendicular to the x-axis.

5 0
2 years ago
The diagram shows two similar vases, A and B<br>The height of vase A is 9 cm and the height of vase B is 13 cm.<br>Given tha​
Katen [24]

Answer:

Could you elaborate on the question?

8 0
2 years ago
Health insurers are beginning to offer telemedicine services online that replace the common office visit. A company provides a v
Veronika [31]

Answer:

\text {CI} = (60.54, \: 81.46)\\\\

Therefore, we are 95% confident that actual mean savings for a televisit to the doctor is within the interval of ($60.54 to $81.46)

Step-by-step explanation:

Let us find out the mean savings for a televisit to the doctor from the given data.

Using Excel,

=AVERAGE(number1, number2,....)

The mean is found to be

\bar{x} = \$71  

Let us find out the standard deviation of savings for a televisit to the doctor from the given data.

Using Excel,

=STDEV(number1, number2,....)

The standard deviation is found to be

 s = \$ 22.35

The confidence interval is given by

\text {confidence interval} = \bar{x} \pm MoE\\\\

Where the margin of error is given by

$ MoE = t_{\alpha/2}(\frac{s}{\sqrt{n} } ) $ \\\\

Where n is the sample of 20 online doctor visits, s is the sample standard deviation and t_{\alpha/2} is the t-score corresponding to a 95% confidence level.

The t-score is given by is

Significance level = α = 1 - 0.95 = 0.05/2 = 0.025

Degree of freedom = n - 1 = 20 - 1 = 19

From the t-table at α = 0.025 and DoF = 19

t-score = 2.093

So, the margin of error is

MoE = t_{\alpha/2}(\frac{s}{\sqrt{n} } ) \\\\MoE = 2.093\cdot \frac{22.35}{\sqrt{20} } \\\\MoE = 2.093\cdot 4.997\\\\MoE = 10.46\\\\

So the required 95% confidence interval is

\text {CI} = \bar{x} \pm MoE\\\\\text {CI} = 71 \pm 10.46\\\\\text {CI} = 71 - 10.46, \: 71 + 10.46\\\\\text {CI} = (60.54, \: 81.46)\\\\

Therefore, we are 95% confident that actual mean savings for a televisit to the doctor is within the interval of ($60.54 to $81.46)

7 0
2 years ago
Which group has the higher mean? By how much? Round to the nearest tenth.
vampirchik [111]
Can I ask how did u make the picture? Plz tell me how
7 0
2 years ago
What is 12x-32 answer needed
Rudik [331]

Answer:

plz Mark me brainliest

7 0
3 years ago
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