Which shows the solution set to the

The radius of a circle is 7 centimeters. What is the area?

krek1111 [17]

Answer:

49开

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

A small radio transmitter broadcasts in a 69 mile radius. If you drive along a straight line from a city 93 miles north of the t

larisa86 [58]

Answer:

See Explanation

Step-by-step explanation:

According to the Question,

We have A small radio transmitter that broadcasts in a 69-mile radius. If you drive along a straight line from a city 93 miles north of the transmitter to a second city 78 miles east of the transmitter.

Thus,

The distance that you get reception is the length of the chord created by the intersection of the circle defining the edge of transmission and the line defining the car trip.

x2 + y2 = 69² this is the circle

And,

The Transmitter at the origin

City to the north at (0,93) & City to the east at (78,0)

the Slope is M=(-93/78)

Intercept is B= y - mx ⇒ 93 - (-93/78)(0) = 93

The equation of the line between the cities is y = (-93/78)x + 93

y = -93x/78 + 93 this is the line

Now, Solve the above two Equations

The intersection is gotten from the picture or solving:

x^2 + [(-93/78)*x + 93]^2 = 69^2

on solving we get, the points approximately are: (67.952,11.98 ) and (23.6277, 64.82)

Now,

From the Pythagorean theorem the total distance of the trip is:

d1 = √(93^2 + 78^2) ≈ 121.37miles

And the distance when the signal is picked up is:

d2 =√ [(67.952-23.627)^2 + (64.82 - 11.98)^2] ≈ 68.96 miles

You will pick up a signal from the transmitter in (d2/d1)*100 = 56% of the drive.

3 0

3 years ago

60 cans of soup are arranged to be displayed in 10 rows. Why does the fraction 10 over 60 not represent this situation? Explain.

mojhsa [17]

<u><em>Explanation</em></u>: The reason why is because when divide 10/60 it becomes a decimals and cans can't be decimals, but if you divide 60/10 then it will be 6 cans in each row.

4 0

3 years ago

Help What is the graph???

marin [14]

We are given

$y=\frac{x^2-4x+3}{x^2-9}$

Vertical asymptotes:

Firstly, we will factor numerator and denominator

we get

$y=\frac{(x-1)(x-3)}{(x-3)(x+3)}$

We can see that (x-3) is common in both numerator and denominator

so, we will only set x+3 to 0

and then we can find vertical asymptote

$x+3=0$

$x=-3$

Hole:

We can see that (x-3) is common in both numerator and denominator

so, hole will be at x-3=0

$x=3$

Horizontal asymptote:

We can see that degree of numerator is 2

degree of denominator is also 2

for finding horizontal asymptote, we find ratio of leading coefficients of numerator and denominator

and we get

y=1

now, we can draw graph

Graph:

6 0

3 years ago

Can anyone please help!!!

quester [9]

Answer:

Question 9

(a) The distance, Jalaj walks in one day is 4.4 km

(b) The amount Jalaj raises after walking for 22 km at the end of the 5 days is $8

Question 10

(b) The difference between the largest and smallest areas is 2,400 m²

Step-by-step explanation:

Question 9

(a) The distance Jalaj walks in 5 days = 22 km

Whereby Jalaj walks equal distance every day, we have;

The distance, Jalaj walks in one day = 22 km/5 days = 4.4 km/day

The distance, Jalaj walks in one day = 4.4 km

(b) The amount he raises for every kilometer he walks = $1.60

The amount he raises after walking for 22 km at the end of the 5 days = 5 × $1.60 = $8

Question 10

(b) The given side length of the square = 120 meters to the nearest 10 meters

Therefore;

The maximum dimension for the side length of the square = 120 + 10/2 = 125

The largest possible area of the square, $A_l$ = 125 m × 125 m = 15,625 m²

The minimum dimension for the side length of the square = 120 m - 10 m/2 = 115 m

The smallest possible area of the square, $A_s$ = 115 m × 115 m = 13,225 m².

The difference between the largest and smallest areas, $A_l$ - $A_s$ = 15,625 - 13,225 = 2,400 m².

8 0

3 years ago