a map shows the town where niko lives. the actual distance from niko's house to his school is 3miles, and measures one-half inch
2 answers:
Answer:
<h2>4 miles would be 2-thirds inch on the map.</h2>Step-by-step explanation:
The entire question is:
A map shows the town where Niko lives. The actual distance from Niko's house to his school is 3 miles and measures one-half inch on the map. The actual distance from Niko's school to the library is 4 miles. How long is this distance on the map?
To solve this problem, we can apply the rule of three, if 3 miles are one-half inch on the map, how long would be on the map for 4 miles.
Therefore, 4 miles would be 2-thirds inch on the map.
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Answer:
578 + 48 square inches
Step-by-step explanation:
The computation of the area of the purple band is as follows:
Area of the green square = side^2 = x^ square inches
And, the area of the orange square = side^2
The side would be = = 12 + 12 +x = 24 + x
And, now the area would be = (x + 24)^2
Now the area of the orange band is
= Area of the orange square area of the green square
= (x + 24)^2 - x^2
= x^2 + 24^2 + 48 - x^2
= 578 + 48 square inches
The equation that matches the given table is
y = 10x + 40
Solution:
General equation of a line : y = mx + c
Let us find the equation of the table.
<u>Common differences of X: </u>
0 – 1 = 1, 1 – 2 = 1, 3 – 2 = 1, 4 – 3 = 1, 5 – 4 = 1
<u>Common differences of Y: </u>
50 – 40 = 10, 60 – 50 = 10, 70 – 60 = 10, 80 – 70 = 10, 90 – 80 = 10
m = 10
Substitute m = 10 in general equation of a line
y = 10x + c
To find the constant term, substitute x = 0 and y = 40.
40 = 10(0) + c
40 = 0 + c
40 = c
c = 40
Therefore the equation of a line is y = 10x + 40.
Hence the equation that matches the given table is y = 10x + 40.