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noname [10]
2 years ago
10

The Mad Hatter is ordering cups from Teacups

Mathematics
1 answer:
Flura [38]2 years ago
3 0

a) The piecewise function is:

C(n) = 12 + 1.40n, n \leq 20

C(n) = 15 + 1.1n, n > 20

b) Applying the piecewise function, it is found that it will cost $40.

A <u>piecewise function</u> is a function that has different definitions based on the input.

Item a:

  • <u>20 or fewer cups</u>, fixed cost of $12 for shipping plus $1.40 per cup. Thus, the <em>first definition</em> of the function for the cost of n cups is:

C(n) = 12 + 1.40n, n \leq 20

  • For <u>more than 20 cups</u>, price of $1.1 per cup plus a shipping and handling fee of $15. Then:

C(n) = 15 + 1.1n, n > 20

Then, the piece-wise function is:

C(n) = 12 + 1.40n, n \leq 20

C(n) = 15 + 1.1n, n > 20

Item b:

  • The cost of 20 cups is C(20).
  • It is the first definition, which is valid for n \leq 20.

Then:

C(20) = 12 + 1.4(20) = 12 + 28 = 40

It will cost $40.

A similar problem is given at brainly.com/question/24815096

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How many unique triangles can be drawn with side lengths 8 in., 12 in., and 24 in.? Explain
Debora [2.8K]

By using the triangular inequality, we will see that no triangles can be made with these side lengths.

<h3>How many triangles can be made with these side lengths?</h3>

Remember that for any triangle with side lengths A, B, and C, the triangular inequality must be true.

This means that the sum of any two sides must be larger than the other side.

A + B > C

A + C > B

B + C > A.

For the given side lengths, we will have:

8 in + 12 in > 24 in

8in + 24 in > 12 in

12 in + 24 in > 8 in.

Now, notice that the first inequality is false. So the triangular inequality is not meet. Then we can't make a triangle with these side lengths.

So we can make 0 unique triangles with these side lengths.

If you want to learn more about triangles:

brainly.com/question/2217700

#SPJ1

5 0
2 years ago
Rebecca had 9/10 of a yard of ribbon.Rebecca had 9/10 of a yard of ribbon. Then she gave 7/20 of a yard to a friend. How much do
scZoUnD [109]
I think it's 11/20.
6 0
3 years ago
3/4 of the weight of a bunch of grapes is equivalent to 3/5 of the weight of a papaya. If the grapes way (X +28) pounds what is
Margaret [11]
Let p = weight of papaya and g = weight of grapes.

Then (3/4)g = (3/5)p.  Since the weight of grapes is x + 28, 

(3/4)(x + 28) = (3/5)p.  We must solve for x.  To do this, mult. both sides by (5/3):

(5/3)(3/4)(x+28) = (5/3)(3/5)p

Then p = (15/9)(x+28), or (after reduction), p = (5/3)(x+28).


4 0
3 years ago
Exercice 2:
asambeis [7]

Answer:

this question is wrong

8 0
3 years ago
Please solve them fast I need them
ser-zykov [4K]

Answer:

i dont see anything

Step-by-step explanation:can you put more details?

6 0
3 years ago
Read 2 more answers
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