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sergeinik [125]
2 years ago
15

Factor completely -2x^4+6x^3+8x^2

Mathematics
1 answer:
vlada-n [284]2 years ago
5 0

Answer:

-2x²(x + 1)(x - 4)

Step-by-step explanation:

Hello!

Factor:

  • -2x^4 + 6x^3 + 8x^2
  • -2x^2(x^2 - 3x - 4)        Take out GCF

Think: What numbers add up to -3 and multiply to -4?

Answer: -4 and 1

Continue:

  • -2x^2(x^2 - 3x - 4)
  • -2x^2(x^2 - 4x + x - 4)
  • -2x^2(x(x - 4) + 1(x - 4))       Factor by Grouping
  • -2x^2(x + 1)(x - 4)

The complete factored form is -2x²(x + 1)(x - 4)

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Which expression is equivalent to (73)-2
padilas [110]

Answer:

73*-2 =-146 you have to multiply the 73 to the -2

Step-by-step explanation:

6 0
3 years ago
Find the intersection points using substitution or elimination for each system of equations:
natka813 [3]

Answer:

Step-by-step explanation:

Okay, so I think I know what the equations are, but I might have misinterpreted them because of the syntax- I think when you ask a question you can use the symbols tool to input it in a more clear way, otherwise you can use parentheses and such.

Problem 1:

(x²)/4 +y²= 1

y= x+1

*substitute for y*

Now we have a one-variable equation we can solve-

x²/4 + (x+1)² = 1

x²/4 + (x+1)(x+1)= 1

x²/4 + x²+2x+1= 1

*subtract 1 from both sides to set equal to 0*

x²/4 +x^2+2x=0

x²/4 can also be 1/4 * x²

1/4 * x² +1*x² +2x = 0

*combine like terms*

5/4 * x^2+2x+ 0 =0

now, you can use the quadratic equation to solve for x

a= 5/4

b= 2

c=0

the syntax on this will be rough, but I'll do my best...

x= (-b ± √(b²-4ac))/(2a)

x= (-2 ±√(2²-4*(5/4)*(0))/(2*(5/4))

x= (-2 ±√(4-0))/(2.5)

x= (-2±2)/2.5

x will have 2 answers because of ±

x= 0 or x= 1.6

now plug that back into one of the equations and solve.

y= 0+1 = 1

y= 1.6+1= 2.6

Hopefully this explanation was enough to help you solve problem 2.

Problem 2:

x² + y² -16y +39= 0

y²- x² -9= 0

6 0
3 years ago
1.3.IP-28
lidiya [134]

Step-by-step explanation:

Find the difference

3,621 - 1,836 = 1,785

They payed $1,785 dollars in the second installment.

6 0
3 years ago
7.7.33
GenaCL600 [577]
We know that

At sea level, the height is 0 and
the pressure is 98 kilopascals

At 1000 ft, the height is 1000 and
the pressure <span>decreases about 11.41%

</span>i(100%-11.41%)/100----> (0.8859)

therefore
1) at 1000 ft--------> the pressure is 98*(0.8859)----------> 86.82 kilopascals
2) at 2000 ft--------> the pressure is 86.82*(0.8859)-------> 76.91 kilopascals
3) at 3000 ft--------> the pressure is 76.91*(0.8859)-------> 68.14 kilopascals
4) at 4000 ft---------> the pressure is 68.14*(0.8859)-------> 60.36 kilopascals


the answer is
<span>The pressure at an altitude of 4000 m is about </span>60.36 kilopascals
7 0
3 years ago
Cameron has decided to diversify his investments in the following way $3000 in an account earning 2.7% simple interest $5000 in
jolli1 [7]
A=3000(1+3*0.027)=3,243
Interest earned 243
A=5,000×(1+0.018)^(3)=5,274.89
Interest earned 274.89
A=5,000×(1+0.039÷4)^(4×3)=5,617.41
Interest earned 617.41

Total interest 243+274.89+617.41=1,135.3
Total amount Amount after 3 years
3,243+5,274.89+5,617.41=14,135.3
3 0
3 years ago
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