We write the equation in terms of dy/dx,
<span>y'(x)=sqrt (2y(x)+18)</span>
dy/dx = sqrt(2y + 18)
dy/dx = sqrt(2) ( sqrt(y + 9))
Separating the variables in the equation, we will have:
<span>1/sqrt(y + 9) dy= sqrt(2) dx </span>
Integrating both sides, we will obtain
<span>2sqrt(y+9) = x(sqrt(2)) + c </span>
<span>where c is a constant and can be determined by using the boundary condition given </span>
<span>y(5)=9 : x = 5, y = 9
</span><span>sqrt(9+9) = 5/sqrt(2) + C </span>
<span>C = sqrt(18) - 5/sqrt(2) = sqrt(2) / 2</span>
Substituting to the original equation,
sqrt(y+9) = x/sqrt(2) + sqrt(2) / 2
<span>sqrt(y+9) = (2x + 2) / 2sqrt(2)
</span>
Squaring both sides, we will obtain,
<span>y + 9 = ((2x+2)^2) / 8</span>
y = ((2x+2)^2) / 8 - 9
What is it
I don't get it done
Y=2x
..........................................
This is an incomplete question, the image is shown below.
Answer : The fraction empty container is, 
Step-by-step explanation :
As we are given that:
The capacity of container = 60 mL
In the given figure, the container is filled with 25 mL.
That means,
60 - 25 = 35 mL container is empty.
Now we have to calculate the fraction of it is empty.
The fraction of it is empty = 
The fraction of it is empty = 
The fraction of it is empty =
Therefore, the fraction empty container is,
Answer:
The representative sample contained more girls than boys.
