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ANEK [815]
2 years ago
13

Which are the better statistics to use to compare the team scores? Team A's scores 58 60 62 64 66 68 70 72 74 76 78 80 82 84 86

88 90 92 94 96 98 100 Team B's scores 58 60 62 64 66 68 70 72 74 76 78 80 82 84 86 88 90 92 94 96 98 100 O
A. Median and standard deviation O
B. Mean and standard deviation O
C. Mean and IQR O
D. Median and IQR​

Mathematics
1 answer:
Alenkasestr [34]2 years ago
4 0

The better statistics that can be used to compare the scores of the two teams are: <u>D. Median and IQR​.</u>

  • The diagram given shows two box plots representing the data of the two team's scores.

<u><em>Box plots</em></u><u><em> displays the </em></u><u><em>5-number summary</em></u><u><em>, namely:</em></u>

  • Minimum data value
  • Maximum data value
  • Median
  • First Quartile (Q_1), and
  • Third Quartile (Q_3)

The Interquartile Range (IQR) of the data can also be calculated by finding the difference between the First Quartile (Q_1), and the Third Quartile (Q_3).

The Interquartile Range (IQR) helps us to determine the variability of the data set.

The median that is gotten from the box pot measures the center tendency of the data.

Both median and IQR are better statistics that can be easily gotten from box plots to compare the team scores.

Therefore, the better statistics to use for comparing the scores of the teams are: <u>D. Median and IQR​.</u>

Learn more here:

brainly.com/question/15800880

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3 0
3 years ago
Read 2 more answers
-3.75+2(-4x+6.1)-3.25
Pani-rosa [81]

The value of x is 0.65

<u>Step-by-step explanation:</u>

This solution is given by solving the given problem using BODMAS rule.

This means that the steps to be followed to find the solution should be in the order of BODMAS rule.

B- Bracket, O- of, D- Division, M- Multiplication, A- Addition, S- Subtraction.

This rule states that the 1st operation must be done for Brackets.

⇒ -3.75+2(-4x+6.1)-3.25 = 0

⇒ -3.75 -8x + 12.2 -3.25 = 0

The addition operation should be performed next and then followed by subtraction.

⇒ -8x -7+ 12.2 = 0

<u>To find the value of x :</u>

Keeping the x term alone on one side and moving the constants on other side,

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3 0
3 years ago
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