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Savatey [412]
3 years ago
9

Can someone help and quick plsss

Mathematics
1 answer:
BartSMP [9]3 years ago
6 0

Answer:

c. :)

Step-by-step explanation:

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27.1% of city employees ride the bus to work. This is up 47% from last year. What percent of employees rode the bus to work last
dolphi86 [110]

Answer:

18.44%

Step-by-step explanation:

Let :

Percentage who rode bus to work last year = x

Percentage who ride bus to work this year = 27.1%

Percentage who ride bus to work this year = [percentage who rode bus to work last year + 47% of percentage who rode bus to work last year]

Mathematically ;

27.1% = x + 47% of x

0.271 = x + (0.47x)

0.271 = x + 0.47x

0.271 = 1.47x

x = 0.271 / 1.47

x = 0.1843537

x = 0.1843537 * 100%

x = 18.435%

x = 18.44%

4 0
3 years ago
Iew
Contact [7]

Answer:x

Step-by-step explanation:

6 0
3 years ago
A solution is prepared by dissolving
Whitepunk [10]

Answer:

13.79%

Step-by-step explanation:

A solution is made by dissolving 24 millimeters of saline in 150 millimeters of pure solution

Therefore percent of saline in the pure solution can be calculated as follows

= 24/24+150 × 100

= 24/174 ×100

= 0.1379 ×100

= 13.79%

Hence the percent of saline in the pure solution is 13.79%

8 0
4 years ago
The area of a rectangle was 15 cm. Every dimension was multiplied by a scale factor and the new area was 3.75 cm. What was the s
Pavlova-9 [17]
The scale factor was .25
4 0
4 years ago
Majesty Video Production Inc. wants the mean length of its advertisements to be 24 seconds. Assume the distribution of ad length
oksano4ka [1.4K]

Answer:

It is going to be bell-shaped(normally distributed), with mean \mu = 24 and standard deviation s = \frac{2}{\sqrt{15}} = 0.5164.

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, a large sample size can be approximated to a normal distribution with mean \mu and standard deviation \frac{\sigma}{\sqrt{n}}.

What can we say about the shape of the distribution of the sample mean time?

It is going to be bell-shaped(normally distributed), with mean \mu = 24 and standard deviation s = \frac{2}{\sqrt{15}} = 0.5164.

4 0
4 years ago
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