Answer:
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Check the picture.
The figure shows lines m, n and the line through points A And B, call it

.
1. The angles ABC and CBP are "supplementary" angles, that is angles whose sum is 180°, because together they form one straight angle.
thus,
(2x+5°)+(7x-14°)=180°
9x-9°=180°
9x=189°
x=189°/9=21°.
2. Remark, m and n are parallel, otherwise we can say nothing about the measure of angle P
check the second picture, notice the F shape formed by CBP and P.
Angles CBP and P are called "angles F" or "corresponding angles".
Corresponding angles formed by a line cutting 2 parallel lines, are always congruent (that is equal) so:
m(P)=m(CBP)=7x-14°=7.21°-14°=147°-14°=133°
Answer: 133°
2:4:6 =2x :4x :6x
2x -1st angle
4x -2d one
6x - 3d one
2x+4x+6x=180 because MNO is a triangle
12x=180
x=180/12=15
2*15=30° -1st angle
4*15= 60° -2d one
6*15=90° - 3d one
The points it gives you are y intercepts, and because you’re trying to find lines parallel- the only thing that changes for the equation is the y intercept.
1) y=2x+4
2) y=-x+7
3)y=-8x-2
Answer:
The maximum height of the projectile is 90 ft
Step-by-step explanation:
Here, we want to get the maximum height reached by the projectile
The answer here will be the y-coordinate value of the vertex form of the given equation
so firstly, we have to write the equation in the vertex form
We have this as;
y = -16t^2 + 64t + 26
That will be;
y = a(x-h)^2 + k
y = -16(x-2)^2 + 90
where the vertex of the equation is;
(-h,k)
K
in this case is 90 and thus, that is the maximum height of the projectile