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denis23 [38]
2 years ago
7

While holding her puppy, Tammy steps on a scale. The scale reads 127 pounds. Alone, Tammy weighs 112 pounds. Write and solve an

addition equation to find the weight of Tammy's puppy. Use the variable P.
Mathematics
1 answer:
sleet_krkn [62]2 years ago
5 0
Equation: 127-112=P
answer:P=15
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If the length of a rectangle is 3 feet less then twice its width and the area is 54square feet what are its dimensions
erma4kov [3.2K]
The length (L) of the rectangle can be written as a function of the width (W)L = 2W - 3:
Now since we know Area = Width*Length, we can write the area as a function of the width:
A = L*W = (2W-3)*W
Distributing the W inside the parentheses we have:
A = 2W^2 - 3W
We know the area is 54 ft^2, so we can rewrite it as:
2W^2 - 3W - 54 = 0
Now solve for W by factoring (or by applying the quadratic formula):
2W^2 - 12W + 9W - 54 = 0
Factor out a common 2W from the first two terms and a 9 from the last two terms:
2W(W-6) + 9(W-6) = 0
Regroup the terms to get our fully factored equation:
(2W + 9)(W-6) = 0
This gives us the roots W = 6 and W = -9/2, but width can't be negative so we have width = 6 ft. Then remember that the length L = 2W - 3, so our length is:
L = 2W - 3 = 2(6) - 3 = 12 - 3 = 9
So now we know that our rectangle is 9 feet long and 6 feet wide.
5 0
4 years ago
The ratio of neutrons in the nucleus of atom A to atom B is 6 to 7. If there are 54 neutrons in the nucleus of atom A.Find the n
galina1969 [7]

Answer:

b

Step-by-step explanation:

4 0
4 years ago
Which set of points are on the line y=2x-3?
Fed [463]
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5 0
3 years ago
Name Date 34bral Kuta Software - Infinite Algebra 2 Solving Absolute Value Equations Solve each equation. 1) 13x1=9 2) 1-3r1=9 R
vichka [17]
-5|3+4k|=-115

start by dividing both sided by -5

\frac{-5}{-5}|3+4k|=-\frac{115}{-5}|3+4k|=23

when we have an absolute we obtain two equations, one for the positive value and one for the negative value

\begin{gathered} 3+4k=23 \\ -(3+4k)=23 \end{gathered}

solve each of them

\begin{gathered} 3+4k=23 \\ 4k=23-3 \\ 4k=20 \\ k=\frac{20}{4}=5 \end{gathered}

for the second equation

\begin{gathered} -(3+4k)=23 \\ -3-4k=23 \\ -4k=23+3 \\ -4k=26 \\ k=-\frac{26}{4}=-6.5 \end{gathered}

the solutions for k are -6.5 and 5

4 0
1 year ago
Find the value of x<br><br> Help please
dimulka [17.4K]

Answer:

isnt it 41

Step-by-step explanation:

5 0
3 years ago
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