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denis23 [38]
2 years ago
7

While holding her puppy, Tammy steps on a scale. The scale reads 127 pounds. Alone, Tammy weighs 112 pounds. Write and solve an

addition equation to find the weight of Tammy's puppy. Use the variable P.
Mathematics
1 answer:
sleet_krkn [62]2 years ago
5 0
Equation: 127-112=P
answer:P=15
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In order to join an online tutoring group, there is a $40
Murljashka [212]

Answer:

<em>it would take you thirteen months</em>

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4 0
2 years ago
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Your Turn: Find the measure of angle P below. Show your work. *
Virty [35]
Check the picture.

The figure shows lines m, n and the line through points A And B, call it l_{AB}.

1. The angles ABC and CBP  are  "supplementary" angles, that is angles whose sum is 180°, because together they form one straight angle.

thus, 

(2x+5°)+(7x-14°)=180°

9x-9°=180°

9x=189°

x=189°/9=21°.


2. Remark, m and n are parallel, otherwise we can say nothing about the measure of angle P

check the second picture, notice the F shape formed by CBP and P.

Angles CBP and P are called "angles F" or "corresponding angles".

Corresponding angles formed by a line cutting 2 parallel lines, are always congruent (that is equal) so:

m(P)=m(CBP)=7x-14°=7.21°-14°=147°-14°=133°


Answer: 133°

5 0
3 years ago
Read 2 more answers
Determine the measures of the angles of MNO if the measures of the angles are in the ratio 2:4:6
saul85 [17]
2:4:6 =2x :4x :6x
2x -1st angle
4x -2d one
6x - 3d one
2x+4x+6x=180 because MNO is a triangle
12x=180
x=180/12=15

2*15=30° -1st angle
4*15= 60° -2d one
6*15=90° - 3d one


4 0
3 years ago
Write an equation of the line that is parallel to the given line and passes through the given point.
castortr0y [4]
The points it gives you are y intercepts, and because you’re trying to find lines parallel- the only thing that changes for the equation is the y intercept.

1) y=2x+4
2) y=-x+7
3)y=-8x-2
6 0
2 years ago
The path of a projectile launched from a 26-ft-tall tower is modeled by the equation y = −16t2 + 64t + 26. What is the maximum h
BabaBlast [244]

Answer:

The maximum height of the projectile is 90 ft

Step-by-step explanation:

Here, we want to get the maximum height reached by the projectile

The answer here will be the y-coordinate value of the vertex form of the given equation

so firstly, we have to write the equation in the vertex form

We have this as;

y = -16t^2 + 64t + 26

That will be;

y = a(x-h)^2 + k

y = -16(x-2)^2 + 90

where the vertex of the equation is;

(-h,k)

K

in this case is 90 and thus, that is the maximum height of the projectile

8 0
3 years ago
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