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ASHA 777 [7]
3 years ago
7

What is the cube of the square of the second smallest prime number?

Mathematics
1 answer:
o-na [289]3 years ago
3 0

Answer:8

Step-by-step explanation:

The smallest prime is 2

cube of 2 is equal to 8

2*2*2=8

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2

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If a student has an average exam score between 70 and​ 79, he will earn a grade of C in his algebra course. Suppose he has three
goldenfox [79]

Answer:

(64,86.5)

Step-by-step explanation:

find the case where he gets 70 and the case where he gets 79

if his average is 70:

(75+62+85+2x)/5=70

(222+2x)/5=70

222+2x=350

2x=128

x=64

if his average is 79:

(75+62+85+2x)/5=79

(222+2x)/5=79

222+2x=395

222+2x=395

2x=173

x=86.5

7 0
3 years ago
When evaluating proportions, we write the ratios in fractional form and then we ________________.
soldi70 [24.7K]
Set the cross products equal
3 0
3 years ago
En un triangulo ABC, el angulo B mide 64° y el angulo C mide 72°. La bisectriz interior CD corta a la altura BH y a la bisectriz
nadezda [96]

Answer:

The difference between the greatest and the smallest angle of the triangle PBQ is 98°.

Step-by-step explanation:

The question is:

In a triangle ABC, angle B measures 64 ° and angle C measures 72°. The inner bisector CD intersects the height BH and the bisector BM at P and Q respectively. Find the difference between the greatest and the smallest angle of the triangle PBQ.

Solution:

Consider the triangle ABC.

The measure of angle A is:

angle A + angle B + angle C = 180°

angle A = 180° - angle B - angle C

             = 180° - 72° - 64°

             = 44°  

It is provided that CD and BM are bisectors.

That:

angle BCP = angle PCH = 36°

angle CBQ = angle QBD = 32°

angle BHC = 90°

Compute the measure of angle HBC as follows:

angle HBC = 180° - angle BHC + angle BCH

                  = 180° - 90° - 72°

                  = 18°

Compute the measure of angle BPC as follows:

angle BPC = 180° - angle PCB + angle CBP

                  = 180° - 18° - 36°

                  = 126°

Then the measure of angle BPQ will be:

angle BPQ = 180° - angle BPC

                  = 180° - 126°

angle BPQ = 54°

Compute the measure of angle PBQ as follows:

angle PBQ = angle B - angle QBD - angle HBC

                  = 64° - 32° - 18°

angle PBQ = 14°

Compute the measure of angle BQP as follows:

angle BQP = 180° - angle PBQ - angle BPQ

                  = 180° - 14° - 54°  

angle BQP = 112°

So, the greatest and the smallest angle of the triangle PBQ are:

angle BQP = 112°

angle PBQ = 14°

Compute the difference:

<em>d</em> = angle BQP - angle PBQ

  = 112° - 14°

  = 98°

Thus, the difference between the greatest and the smallest angle of the triangle PBQ is 98°.

4 0
3 years ago
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