What is the cube of the square of the second smallest prime number?
1 answer:
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The probability that the mean clock life would differ from the population mean by greater than 12.5 years is 98.30%.
Given mean of 14 years, variance of 25 and sample size is 50.
We have to calculate the probability that the mean clock life would differ from the population mean by greater than 1.5 years.
μ=14,
σ==5
n=50
s orσ =5/=0.7071.
This is 1 subtracted by the p value of z when X=12.5.
So,
z=X-μ/σ
=12.5-14/0.7071
=-2.12
P value=0.0170
1-0.0170=0.9830
=98.30%
Hence the probability that the mean clock life would differ from the population mean by greater than 1.5 years is 98.30%.
Learn more about probability at brainly.com/question/24756209
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There is a mistake in question and correct question is as under:
What is the probability that the mean clock life would differ from the population mean by greater than 12.5 years?
Answer:
2
Step-by-step explanation:
We need to plot the points in a graph and see the general shape of the curve.
<em>Attached is the graph.</em>
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This Upside Down "U" shaped curve is that of a parabola, which has the general form
Thus, we see, the function is a 2nd degree function, highest power is 2.
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Answer:
The probability that the student is going to pass the test is 0.0545
Step-by-step explanation:
The variable that says the number of correct questions follows a Binomial distribution, because there are n identical and independent events with a probability p of success and a probability 1-p of fail. So, the probability of get x questions correct is:
Where n is equal to 10 questions and p is the probability of get a correct answers, so p is equal to 1/2
Then, if the student pass the test with at least 8 questions correct, the probability P of that is:
P = P(8) + P(9) + P(10)
P = 0.0439 + 0.0097 + 0.0009
P = 0.0545