To prepare 0.250 M solution, the 0.0667 mol of KCl should be diluted up to 266.8mL
<h3>Stoichiometry</h3>
From the question,
We are to determine to what volume the KCl should be diluted, in order to prepare 0.250 M solution
From the formula,
Numer of moles = Concentration × Volume
Then, we can write that
From the given information,
Number of moles = 0.0667 mole
Concentration = 0.250 M
Then,
Volume = 0.2668 L
Volume = 266.8 mL
Hence, to prepare 0.250 M solution, the 0.0667 mol of KCl should be diluted up to 266.8mL
Learn more on Stoichiometry here: brainly.com/question/16632398