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maw [93]
3 years ago
11

Lead nitrate (Pb(NO3)2) solution reacts with potassium iodide (KI) solution to form lead iodide (PbI2) precipitate. How would yo

u characterize this reaction?
Chemistry
1 answer:
dexar [7]3 years ago
7 0

Answer:

Double displacement reaction  

Explanation:

Cuz both the anions and cations from reagents flipped on product side.

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Answer: The ion formed after the reduction of bromine is Br^-

Explanation:

The electronic configuration of Sodium (Na) = [Ne]3s^1

The electronic configuration of Bromine (Br) = [Ar]3d^{10}4s^24p^5

From the above configurations, Sodium ion will loose 1 electron in order to gain stable electronic configuration and that electron is accepted by the Bromine atom because it is 1 electron short of the stable electronic configuration.

Na\rightarrow Na^++e^-   (oxidation reaction)

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Bromine atom is reduced to form Br^-

Reduction reactions are the reactions in which the element gain electrons.

Oxidation reactions are the reactions in which the element looses its electrons.

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