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2 years ago

11

Lead nitrate (Pb(NO3)2) solution reacts with potassium iodide (KI) solution to form lead iodide (PbI2) precipitate. How would yo

u characterize this reaction?

1 answer:

dexar [7]2 years ago

7 0

Answer:

Double displacement reaction

Explanation:

Cuz both the anions and cations from reagents flipped on product side.

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What is the percentage of nitrogen, by mass, in calcium nitrate?.

SCORPION-xisa [38]

Answer:

<em>Nitrogen = 17.07%</em>

Explanation:

We are asked to calculate the percentage by mass of nitrogen in Ca(NO3)2.

The molar mass of calcium nitrate is 164,088 g/mol.

In this 164.088 g/mol there are 2 nitrogen atoms.

Molar mass of nitrogen = 14,0067 g/mol

% Nitrogen = molar mass of N/total molar mass of the compound

% Nitrogen =[(2 x 14.0067)/164.088]*100

% Nitrogen = 17.07%

Please mark me as brainliest if you found this answer helpful

7 0

2 years ago

The population of the world nearly doubled between the years of 1965 and 2000.

den301095 [7]

True. The world population in 1965 was 3.324 billion . In 2000 the world population was 6.115 billion. The difference is 2.791.

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3 years ago

why does ice float on water? the temperature of ice is lower than the temperature of water. the temperature of water and ice are

Andrew [12]

The density of ice is less than the density of water.

Fun fact: Water is the only known liquid that has this change it density.

4 0

3 years ago

Read 2 more answers

HELP ME PLEASE (brainliest)

Aloiza [94]

Answer: i would say D or the last one.

Explanation: According to the law of conservation of mass, the mass of the products in a chemical reaction must equal the mass of the reactants. The law of conservation of mass is useful for a number of calculations and can be used to solve for unknown masses, such the amount of gas consumed or produced during a reaction.

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7 0

2 years ago

how many kilograms of a 35% m/m sodium chlorate solution is needed to react completely with 0.29 l of a 22% m/v aluminum nitrate

Stolb23 [73]

Answer:- 0.273 kg

Solution:- A double replacement reaction takes place. The balanced equation is:

$3NaClO_3+Al(NO_3)_3\rightarrow 3NaNO_3+Al(ClO_3)_3$

We have 0.29 L of 22% m/v aluminum nitrate solution. m/s stands for mass by volume. 22% m/v aluminium nitrate solution means 22 g of it are present in 100 mL solution. With this information, we can calculate the grams of aluminum nitrate present in 0.29 L.

$0.29L(\frac{1000mL}{1L})(\frac{22g}{100mL})$

= 63.8 g aluminum nitrate

From balanced equation, there is 1:3 mol ratio between aluminum nitrate and sodium chlorate. We will convert grams of aluminum nitrate to moles and then on multiplying it by mol ratio we get the moles of sodium chlorate that could further be converted to grams.

We need molar masses for the calculations, Molar mass of sodium chlorate is 106.44 gram per mole and molar mass of aluminum nitrate is 212.99 gram per mole.

$63.8gAl(NO_3)_3(\frac{1mol}{212.99g})(\frac{3molNaClO_3}{1molAl(NO_3)_3})(\frac{106.44g}{1mol})$

= $95.7gNaClO_3$

sodium chlorate solution is 35% m/m. This means 35 g of sodium chlorate are present in 100 g solution. From here, we can calculate the mass of the solution that will contain 95.7 g of sodium chlorate and then the grams are converted to kg.

$95.7gNaClO_3(\frac{100gSolution}{35gNaClO_3})(\frac{1kg}{1000g})$

= 0.273 kg

So, 0.273 kg of 35% m/m sodium chlorate solution are required.

7 0

3 years ago