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MA_775_DIABLO [31]
2 years ago
14

What is the area of the regular polygon shown below?

Mathematics
1 answer:
Galina-37 [17]2 years ago
4 0
The answer is: 1372 in. squared

Because the apothem will always be half of the length of one side. The length of one side is 28 in.

The formula for the area is:
Area = (number of sides × length of one side × apothem)/2

Working out:
A = (7 times 28 times 14) divided by 2 = 1372 in. squared

Hope this helps!
Please give Brainliest!
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Answer:

Measure of EF: 1.98

Measure of AB: 6.16

Measure of HI: 12.2

Step-by-step explanation:

Trick I learned that's very helpful when solving these problems: SOH (Sine, Opposite, Hypotenuse)- CAH (Cosine, Adjacent, Hypotenuse)- TOA (Tangent, Opposite, Adjacent)

MEASURE OF EF

you're starting with angle D which is 26 degrees. You have the measure of the Hypotenuse (DF) and you're trying to find the measure of EF (the segment opposite the angle) so you would use Sine

to do the equation, i'm going to use x in place of EF. 0.44 = sin(26)

Formula: sin(angle) = (opposite)/(hypotenuse)

Equation:

0.44 = x/4.5       <----------- multiply by 4.5 to get x by itself

4.5*0.44 = x       <---------- 4.5 times 0.44

1.98= x       <----------------answer

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trying to find hypotenuse and you already have the adjacent angle so you would use cosine. Using y in place of AB. 0.616 = sin(52)

cos(angle) = (adjacent)/(hypotenuse)

cos(52) = 10/y      <------ divide by y

y*0.616 = 10       <------------ divide by 0.616

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y = 6.16    <-----------answer

MEASURE OF HI

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tan(angle) = (opposite)/(adjacent)

tan(42) = 11/z   <------------ multiply z on both sides

z*0.90 = 11  <--------- divide by 0.90 to get z by itself

z = 11/0.90    <-------- divide 11 by 0.90

z = 12.2

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and

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PS. PLZZZZZZZZZZZ give me brainliest!!!

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