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Trava [24]
3 years ago
5

If f(x)=-5x+1 and g(x)=x^3 what is (g°f)(0)?

Mathematics
1 answer:
Yuri [45]3 years ago
8 0
\bf \begin{cases}
f(x)=-5x+1\\
g(x)=x^3\\
(g\circ f)(x)=g(~~f(x)~~)
\end{cases}
\\\\\\
f(0)=-5(0)+1\implies \boxed{f(0)=1}
\\\\\\
g(~~f(x)~~)\implies g(~~f(0)~~)\implies g\left( ~~\boxed{1}~~ \right)=(1)^3\implies g(1)=1
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what do you do before adding the equation so that one variable will be eliminated when you dd them 2x-4y=5 and 6x-3y=10
Naddika [18.5K]
We have a system of equations 2x - 4y = 5 and 6x - 3y = 10.
We want to eliminate one variable when we add up the equations.

If we want to eliminate the x variable, we need to multiply the top, bottom or both of the equations with a number that when the equations are added together will eliminate the x variable.

Multiply the top equation by -3.

-3(2x - 4y) = 5 * -3
-6x + 12y = -15

Now when we add the two equations together, the x's will be eliminated.

-6x + 12y = -15
6x + 6y = 10
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The x's were eliminated.
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55 divided by 5, divided by 5 divided by 5
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Answer:

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Step-by-step explanation:

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Q # 9 help please:The table shows the height of a plant as it grows.What equation in point-slope form gives the plant's height a
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Answer: First option. y-15=5(x-3)

Solution:

We can take any pair of points of the table. For example:

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And we can find the slope m using the following formula:

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Now we can apply the point-slope formula to find the equation of the right line:

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