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PIT_PIT [208]
2 years ago
15

The circumference of a circle is 37.68 inches. What is the circle's radius? Use 3.14 for ​.

Mathematics
1 answer:
antoniya [11.8K]2 years ago
7 0

Answer:

12

Step-by-step explanation:

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Find the difference 7/x^2-3x - 1/x^2-9
Goshia [24]
To solve this problem you must apply the proccedure shown below:

 1. You have the following expression given in the problem above:

 <span>7/x^2-3x - 1/x^2-9
</span>
 2. When you factor the denominator, you obtain:

 <span>7/x(x-3) - 1/(x+3)(x-3)
 

 3. By simplifying the expression, you obtain:

 3(2x+7)/x(x+3)(x-3)
</span> 3(2x+7)/x(x^2-9)

 The answer is: 
 3(2x+7)/x(x^2-9)
6 0
3 years ago
Simplify 10d-3d ? Pls tell me I need help on this
Mariana [72]

Answer:

7d

Step-by-step explanation:

10d-3d  = 7 d

hope it's helpful dear :)

3 0
3 years ago
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State A and state B are among the states with the most remaining drive in movie screens. State A has 4 more screens than state B
mojhsa [17]
State A has 25 drive-in movie screens and State B has 21. You find this by guess-and-checking different numbers that you could add together to get 46. You want to do numbers that are relatively close, as a difference in 4 is not much at all. You can divide 46 by 2 and then play around from there.
6 0
2 years ago
Which proportion could be used to find the length of side b?​
Goshia [24]

Answer:

B

Step-by-step explanation:

Using the Sine Rule in ΔABC

\frac{a}{sinA} = \frac{b}{sinB} = \frac{c}{sinC}

∠C = 180° - (82 + 58)° = 180° - 140° = 40°

Completing values in the above formula gives

\frac{a}{sin58} = \frac{b}{sin82} = \frac{8.4}{sin40}

We require a pair of ratios which contain b and 3 known quantities, that is

\frac{b}{sin82} = \frac{8.4}{sin40}

OR

\frac{sin40}{8.4} = \frac{sin82}{b} → B

8 0
3 years ago
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If he drank 80% of his water on his entire hike, how much did he drink? Explain and show your reasoning with a model.
qwelly [4]
Can you please be more specific? He drank 4/5 of the bottle and if the bottle is a 2 liter bottle, he drank 1.6
5 0
3 years ago
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