Most colleges dont care it all depends on your personal preference which one you want to take
The final rotational speed ω_final and the instantaneous power P delivered to the wheel are; ω_f = √((ω_i)² + 2(FL/(kmr²) and P = Frω_i
<h3>What is the Instantaneous Power?</h3>
A) From rotational kinematics, the formula for the final angular velocity is;
ω_f = √((ω_i)² + 2αθ)
where;
α is angular acceleration
θ = L/r. Thus;
ω_f = √((ω_i)² + 2α(L/r))
Now, α = T/I
Where;
I is moment of inertia = k*m*r²
T is t o r q u e = F * r
Thus;
α = (F * r)/(kmr²)
α = F/(kmr)
ω_f = √((ω_i)² + 2(F/(kmr))(L/r))
ω_f = √((ω_i)² + 2(FL/(kmr²)
B) Formula for instantaneous power is;
P = Fv
where at t = 0; v = rω_i
Thus;
P = Frω_i
Read more about Instantaneous Power at; brainly.com/question/14244672
Answer:
N/A
Explanation:
Need more context. Question is incomplete
The action that the nurse who is caring for a client who is in the transition phase of labor should take is; C. Assist the client with patterned-paced breathing.
<h3>What is the duty of the Nurse?</h3>
The action that the nurse who is caring for a client who is in the transition phase of labor should take is; C. Assist the client with patterned-paced breathing.
The reason is that Patterned breathing refers to the act of breathing at any number of possible rates and depths. Some women prefer breathing deeply, using their diaphragm to fill their abdomen with air. Other women prefer light breathing, inhaling just enough to fill their chest. The goal is to find breathing patterns that have a calming and relaxing effect.
The benefits of patterned breathing are;
- Breathing becomes an automatic response to pain
- The mother remains in a more relaxed state and will respond more positively to the onset of pain
- The steady rhythm of breathing is calming during labor
- Provides a sense of well being and control
- Increased oxygen provides more strength and energy for both the mother and baby
- Brings purpose to each contraction, making contractions more productive
The missing options are;
A. Instruct the client to use effleurage
B. Apply counter pressure to the client sacral.
C. Assist the client with patterned-paced breathing.
D. Teach the client the technique of biofeedback
Read more about Nurse Duty at; brainly.com/question/24331637
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Answer:
0.67038
Explanation:
One z-value is negative and the other is positive.
This means we are looking for area between the two given z-values on opposite sides of the mean.
From z-table attached, the area at z = -2.31 is 0.98956
Also, from the second z-table attached, the area at z = 0.47 is 0.68082
But since we are looking for the area between both z-scores, we will now have;
P(-2.31 < x < 0.47) = (0.98956 + 0.68082) - 1
P(-2.31 < x < 0.47) = 0.67038
