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Yakvenalex [24]
2 years ago
8

25 POINTS And Brainliest!!

Mathematics
1 answer:
tatuchka [14]2 years ago
6 0

The appropriate measure of central tendency is one that shows

difference and is suitable for a scale that is nominal.

Response:

  • The measure of central tendency to use is the <u>mode</u>.

<h3>How can the appropriate measure of central tendency be selected?</h3>

The mean is the sum of the measurements divided by the number count

of the plants.

The mode is the measurement that has the highest frequency.

The median is the measurement of the middle plant when arranged in a

given order according to size.

To argue that there is a difference between the plants, the measure of

central tendency to use is the mode, given that the data involves

measurements which can be expressed in a nominal scale.

Therefore;

  • The measure of central tendency that will be best for Mrs. Hull to use is the<u> mode</u>

Learn more about the measures of central tendencies here:

brainly.com/question/1027437

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The answer is C because it’s the one that makes most sense
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You are getting a line-up ready for a school kickball game. You have 7 girls and 7 boys. The rules state each child must kick th
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Answer:

50,803,200 ways

Step-by-step explanation:

In this situation, since you should alternate girl-boy or boy-girl, the line-up can either start with a boy or a girl kicking which would yield one of the two following patterns:

BGBGBGBGBGBGBG or GBGBGBGBGBGBGB.

For each of those patterns, there are 7! ways to arrange all boys and 7! ways to arrange all girls. The number of ways that a line-up can be made for one round of kicking is:

n=2*7!*7!\\n=2*(7*6*5*4*3*2)^2\\n=50,803,200\ ways

There are 50,803,200 ways to set the line-up.

8 0
4 years ago
Can anyone help me with this​
yaroslaw [1]

Answer:

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Ann is mailing packages. Each small package costs her $2.10 to send. Each large package costs her $3.30. How much will it cost h
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Answer:

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4 0
3 years ago
Read 2 more answers
Suppose there is a 13.9 % probability that a randomly selected person aged 40 years or older is a jogger. In​ addition, there is
Blababa [14]

Answer:

There is a 2.17% probability that a randomly selected person aged 40 years or older is male and jogs.

It would be unusual to randomly select a person aged 40 years or older who is male and jogs.

Step-by-step explanation:

We have these following probabilities.

A 13.9% probability that a randomly selected person aged 40 years or older is a jogger, so P(A) = 0.13.

In​ addition, there is a 15.6% probability that a randomly selected person aged 40 years or older is male comma given that he or she jogs. I am going to say that P(B) is the probability that is a male. P(B/A) is the probability that the person is a male, given that he/she jogs. So P(B/A) = 0.156

The Bayes theorem states that:

P(B/A) = \frac{P(A \cap B)}{P(A)}

In which P(A \cap B) is the probability that the person does both thigs, so, in this problem, the probability that a randomly selected person aged 40 years or older is male and jogs.

So

P(A \cap B) = P(A).P(B/A) = 0.156*0.139 = 0.217

There is a 2.17% probability that a randomly selected person aged 40 years or older is male and jogs.

A probability is unusual when it is smaller than 5%.

So it would be unusual to randomly select a person aged 40 years or older who is male and jogs.

4 0
4 years ago
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