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Gekata [30.6K]
2 years ago
10

If r(x) = 3x – 1 and s(x) = 2x 1, which expression is equivalent to (startfraction r over s endfraction) (6)? startfraction 3 (6

) minus 1 over 2 (6) 1 endfraction startfraction (6) over 2 (6) 1 endfraction startfraction 36 minus 1 over 26 1 endfraction startfraction (6) minus 1 over (6) 1 endfraction
Mathematics
1 answer:
viva [34]2 years ago
7 0

The expression which is equivalent to the given ratio of the two provided binary fraction is startfraction 3 (6) minus 1 over 2 (6) 1 endfraction.

<h3>What is the equivalent expression?</h3>

Equivalent expressions are the expression whose result is equal to the original expression, but the way of representation is different.

The given binary functions are.

r(x) = 3x - 1

s(x) = 2x +1

The expression which has to be found out is,

\left(\dfrac{r}{s}\right)(6)=\left(\dfrac{3(6)-1}{2(6)+1}\right)\\\left(\dfrac{r}{s}\right)(6)=\left(\dfrac{18-1}{12+1}\right)\\\left(\dfrac{r}{s}\right)(6)=\left(\dfrac{17}{13}\right)

Thus, the expression which is equivalent to the given ratio of the two provided binary fraction is startfraction 3 (6) minus 1 over 2 (6) 1 endfraction.

Learn more about the equivalent expression here;

brainly.com/question/2972832

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