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3 years ago

Describe how the graph of y=lxl – 7 is like the graph of y=lxl and how it is different.

Mathematics

1 answer:

kifflom [539]3 years ago

4 0

Answer:

y = |x| is a parent function

y = |x| - 7 is a translation of the parent function vertically by 7 points down

The shape is same, just the entire graph has shifted down.

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sergey [27]

Add then I would divide it

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3 years ago

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makvit [3.9K]

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Michelle's father deposited $1,000 into a savings account when she was born. The annual interest rate is

prohojiy [21]

Answer:

Michelle's age = 16

Step-by-step explanation:

As we know,

Amount = $P (1 + r)^{t}$ where

P = Principal amount

r = rate of interest

t = time

Given ,

P = $1000

r = 4.5 % = $\frac{4.5}{100} = 0.045$

Now,

Given that Amount reaches more than $2000

⇒ $P (1 + r)^{t}$ > 2000

⇒ $1000(1 + 0.045)^{t}$ > 2000

⇒ $(1.045)^{t}$ > 2

Now,

we put the value of t from 0 , 1, 2, ..... untill the above equation does not satisfy

Now,

for t = 0

$(1.045)^{0} = 1 \ngeq 2$

for t = 1

$(1.045)^{1} = 1.045 \ngeq 2$

for t = 2

$(1.045)^{2} = 1.092 \ngeq 2$

for t = 3

$(1.045)^{3} = 1.14 \ngeq 2$

for t = 4

$(1.045)^{4} = 1.19 \ngeq 2$

for t = 5

$(1.045)^{5} = 1.25 \ngeq 2$

for t = 6

$(1.045)^{6} = 1.30 \ngeq 2$

for t = 7

$(1.045)^{7} = 1.36 \ngeq 2$

for t = 8

$(1.045)^{8} = 1.42 \ngeq 2$

for t = 9

$(1.045)^{9} = 1.48 \ngeq 2$

for t = 10

$(1.045)^{10} = 1.55 \ngeq 2$

for t = 11

$(1.045)^{11} = 1.62 \ngeq 2$

for t = 12

$(1.045)^{12} = 1.69 \ngeq 2$

for t = 13

$(1.045)^{13} = 1.77 \ngeq 2$

for t = 14

$(1.045)^{14} = 1.85 \ngeq 2$

for t = 15

$(1.045)^{15} = 1.93 \ngeq 2$

for t = 16

$(1.045)^{16} = 2.02 > 2$

It satisfies at t= 16

∴ we get

Michelle's age = 16

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3 years ago

Analyzing Historical Evidence

Romashka [77]

Answer:its a

Step-by-step explanation:

done it already

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3 years ago

A fractal tree starts with a single tree branch (the trunk). At each stage, each new branch from the previous stage grows two mo

AleksandrR [38]

A) New branch in:

2nd stage=2

3rd stage=4

4th stage=8

which can be listed as 2,4,8,...

Here,

2nd term/1st term=4/2=2

3rd term/2nd term=8/4=2

Since common ratio is 2, the given sequence is geometric sequence.

b) The required function is,

B(n)=2^(n-1)

{just put n=1,2,3.. here to check if it gives accurate no of branches in each step or not}

where n is stage number

c)Using above function to calculate total no of branches growing out in the 8th stage,

B(8)=2^(8-1)=2^7=128

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3 years ago