Question

The coordinates of the vertices of a quadrilateral are (8, 11) (11, 7) (8, 3) (2, 3). What is the area, in square units, of the quadrilateral?​

Answer 1

Check the picture below.

so the quadrilateral is really just a parallelogram below a triangle, so let's simply get the area of each and sum them up.

$\stackrel{\textit{\Large Areas}}{\stackrel{parallelogram}{(6)(4)}~~ + ~~\stackrel{triangle}{\cfrac{1}{2}(6)(4)}}\implies 24~~ + ~~12\implies 36$