Answer:
(c) is m=1 i am working on the other ones
Answer:
A. b(w) = 80w +30
B. input: weeks; output: flowers that bloomed
C. 2830
Step-by-step explanation:
<h3>Part A:</h3>
For f(s) = 2s +30, and s(w) = 40w, the composite function f(s(w)) is ...
b(w) = f(s(w)) = 2(40w) +30
b(w) = 80w +30 . . . . . . blooms over w weeks
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<h3>Part B:</h3>
The input units of f(s) are <em>seeds</em>. The output units are <em>flowers</em>.
The input units of s(w) are <em>weeks</em>. The output units are <em>seeds</em>.
Then the function b(w) above has input units of <em>weeks</em>, and output units of <em>flowers</em> (blooms).
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<h3>Part C:</h3>
For 35 weeks, the number of flowers that bloomed is ...
b(35) = 80(35) +30 = 2830 . . . . flowers bloomed over 35 weeks
Answer:
22.5%
Step-by-step explanation:
The total number of students in percentage terms is 100%
Students that chose others = 100% - 40% - 37.5% = 22.5%
8
Step-by-step explanation:
5×4 equals 120 120 divided by 15 equals 8 which is the answer
Given number is 78/14.
We have to find two whole numbers between which given number 78/14 lies.
Let's convert that into mixed fraction.
To do that we divide 78 by 14 to find the quotient.
We see that 14 goes 5 times into 78 and leaves remainder of 8.
So we can rewrite 78/14 as
.
means little more than 5 but less than 6.
So required two whole numbers are 5 and 6.