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Alexeev081 [22]
2 years ago
10

If 43,560 square feet equals one acre, how many acres are in one square mile?

Mathematics
2 answers:
stepladder [879]2 years ago
8 0

Answer: 640

Step-by-step explanation:

How many acres are there in 1 square mile? There are 640 acres in 1 square mile. To convert from square miles to acres, multiply your figure by 640 (or divide by 0.0015625) .

Sophie [7]2 years ago
7 0

Answer:

640 acres²

Divide the area value by 68

43,560 / 68 = 640

or

1~mile^2 * 640 = 640

<em>you multiply the area value by 640 for each square mile, since there is only one square mile, the answer is 640</em>

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3.14 · 6

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Suppose that we want to test the hypothesis with a significance level (alpha) of .05 that the climate has changed since industri
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Answer: we reject the initial claim

(50. 3802, 51.6198)

Step-by-step explanation:

A)

The initial statement is that the mean temperature throughout history is 50°

This is the null hypothesis and it is denoted as H'

H': u = 50.

After taking a sample of 40 years, we realized that the mean temperature is 51°.

This is the alternative hypothesis, in contradiction to the alternative.

The alternative hypothesis is denoted as H1

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Sample mean (x) = 51

Population standard deviation (σ) = 2

We use a z test to get the value of the test statistics.

We are using a z test because sample size is greater than 30 ( n = 40) and population standard deviation is given.

Z score = x - u/ (σ/√n)

Z score = 51 - 50 / (2/√40)

Z score = 1 / 0.3162

Z score = 3.16

Our level of significance is 5%, and the critical value at this level of significance is 1.645.

By comparing the z score relative to the critical value, since our z score is greater than 1.645, it implies that we are in the rejection region hence we reject the initial claim.

B)

We are to construct a 95% confidence interval for population mean temperature.

For upper limit

u = x + Zα/2 ×(σ/√n)

Where Zα/2 = 1.96 which is the critical value for a two tailed test at 5% level of significance.

For upper limit, we have that

u = 51 + 1.96 × (2/√40)

u = 51 + 1.96 (0.3162)

u = 51 + 0.6198

u = 51.6198.

For lower limit, we have that

u = 51 - 1.96 × (2/√40)

u = 51 - 1.96 (0.3162)

u = 51 - 0.6198

u = 50. 3802.

Hence the 95% confidence level for mean temperature is given as (50. 3802°, 51.6198°)

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Step-by-step explanation:

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