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Sergio039 [100]
3 years ago
15

A cube has a surface area of 24ft. What is the length of one edge of the cube

Mathematics
2 answers:
Dafna1 [17]3 years ago
7 0
The length of one edge would be 2
lara31 [8.8K]3 years ago
5 0
The length of one edge would be 2 fr
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Alex bought six books priced at $8 each. He got a discount of 20% off the total cost. How much did Alex pay for the books? Write
Burka [1]
Six books at 8 dollars each is equivalent to $48.00

You are only paying 80% of that cost (100%-20%)

Therefore you are multiplying 48 by .8 

Your answer should be equal to $38.40
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4 years ago
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Simplify the following expression. 2x-5(2x-7y+3)+(-8)
neonofarm [45]
<span>Equation at the end of step  1  :</span> (2x - 5 • (2x - 7y + 3)) + -8<span> :</span>Pulling out like terms :3.1     Pull out like factors :


  -8x + 35y - 23  =   -1 • (8x - 35y + 23) 

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I need help on this question
kari74 [83]

Angle C and E are supplementary angles and when added together equal 180 degrees.


To find E, subtract C from 180.


E = 180 - 147 = 33


Angle E = 33 degrees.

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4 years ago
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Adult tickets to the fall play cost $8 and student tickets cost $4. the drama class sold 20 more adult tickets than student tick
Ganezh [65]
Let a = Adult tickets, s = Student tickets; we are going to set up a system of equations. 

8a + 4s = 880
a - s = 20

We are going to multiply the second equation by so that we can cancel out one of the variables and solve for the other. This gives you:

8a + 4s = 880
4a - 4s = 20

Notice the s-variables will cancel:

12a = 900
a = 75

Now we plug in the amount of adult tickets to solve for the student ones.

75 - s = 20
- s = - 55

Divide both sides by - 1
s = 55.

There were 55 student tickets sold and 75 adult tickets. 


6 0
3 years ago
Karina is creating two pyramids with the nets below using construction paper. In both nets, all of the triangular faces of the p
sleet_krkn [62]

Answer:

144 sq in

Step-by-step explanation:

Face height=9, bases=6 in

#Assume the pyramid has a square base.

First we need to calculate the perpendicular height of the pyramid:

#Pythagorean \ Theorem\\a^2+b^2=c^2\\9^2-(0.5\times 6)^2=h^2\\72=h^2\\h=\sqrt{72} \ in

Now to find the surface area of each pyramid:

A=lw+l\sqrt{(w/2)^2+h^2}+w\sqrt{(l/w)^2+h^2}\\\\\#w=l=6,h=\sqrt{72}\\\\A=6^2+6\sqrt{(6/2)^2+72}+6\sqrt{(6/6)^2+72}\\\\A\approx 144\ sq \ in

Hence amount of construction paper needed to make each pyramid is 144 sq in

3 0
3 years ago
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