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Strike441 [17]
2 years ago
11

8. A computer application generates a sequence of musical notes using the function f(n) 6(16)", where n is the

Mathematics
1 answer:
s2008m [1.1K]2 years ago
3 0

Applying an exponential property, it is found that the function that will generate the same note sequence as function f(n) is given by:

B. H(n) = 6(2)^{4n}

<h3>What is function for the note sequence?</h3>

The function for the node sequence is defined by:

f(n) = 6(16)^n

A function that will the same note sequence as function f(n) has the same initial value of 6. Additionally, applying an exponential property, we have that:

H(n) = 6(2)^{4n} = 6(2^4)^n = 6(16)^n

Hence option B is correct.

More can be learned about exponential properties at brainly.com/question/25537936

#SPJ1

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The terminal side of an angle in standard position passes through p(–3, –4). what is the value of tangent theta?
astraxan [27]

Answer:

  4/3

Step-by-step explanation:

The tangent of any angle (θ) in standard position that has point (x, y) on its terminal ray is ...

  tan(θ) = y/x

__

For the given point on the terminal side, the tangent is ...

  tan(θ) = (-4)/(-3) = 4/3

_____

<em>Additional comment</em>

There are several ways this can be explained. One of them makes use of the relation between rectangular and polar coordinates:

  (x, y) = (r·cos(θ), r·sin(θ))

Then the ratio y/x is ...

  y/x = (r·sin(θ))/(r·cos(θ)) = sin(θ)/cos(θ) = tan(θ)

6 0
1 year ago
Read 2 more answers
Using the given points and line, determine the slope<br><br> (0,32) and (100,212)
suter [353]
To solve for the slope given two lines, use the formula:

(y₂ - y₁)
----------
(x₂ - x₁)

Set one of the points as (x₁, y₁), and the other as (x₂, y₂).

(x₁, y₁) = <span>(0,32)
</span>(x₂, y₂) <span>= (100,212)

plug into corresponding places:


</span>(y₂ - y₁)         (212 - 32)     (180)
----------    =  -------------- = -------
(x₂ - x₁)         (100 - 0)       (100)


180/100 
is your slope

If you want simplified, it will be: 9/5

hope this helps


5 0
3 years ago
A random sample of size 15 taken from a normally distributed population revealed a sample mean of 75 and a sample variance of 25
GREYUIT [131]

Answer:

The upper limit of a 95% confidence interval for the population mean would equal 83.805.

Step-by-step explanation:

The standard deviation is the square root of the variance. Since the variance is 25, the sample's standard deviation is 5.

We have the sample standard deviation, not the population, so we use the t-distribution to solve this question.

T interval:

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 15 - 1 = 14

Now, we have to find a value of T, which is found looking at the t table, with 14 degrees of freedom(y-axis) and a confidence level of 0.95(t_{95}). So we have T = 1.761

The margin of error is:

M = T*s = 1.761*5 = 8.805.

The upper end of the interval is the sample mean added to M. So it is 75 + 8.805 = 83.805.

The upper limit of a 95% confidence interval for the population mean would equal 83.805.

4 0
3 years ago
Find 5 consecutive integers whose sum is 244
storchak [24]

So the first integer is 61.

Then the others must be 62, 63, and 64. To check, you can add them all together. 61+62+63+64=250.

4 0
3 years ago
Help me find the answer
never [62]
The answer is letter C.
7 0
3 years ago
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