3√(-50) = 3√(-1*50)=3i√(25*2) = 3*5i√2=15i√2
Answer:
$15.50
Step-by-step explanation:
0.5 (1) + 5 (3)
0.5 + 15
15.50
The answer of the next term is 31
Answer:
![x =320](https://tex.z-dn.net/?f=x%20%3D320)
Step-by-step explanation:
Given
![x^2 + 200x = 166400](https://tex.z-dn.net/?f=x%5E2%20%2B%20200x%20%3D%20166400)
Required
Find x
We have:
![x^2 + 200x = 166400](https://tex.z-dn.net/?f=x%5E2%20%2B%20200x%20%3D%20166400)
Rewrite as:
![x^2 + 200x - 166400 = 0](https://tex.z-dn.net/?f=x%5E2%20%2B%20200x%20-%20166400%20%3D%200)
Expand
![x^2 + 520x - 320x - 166400 = 0](https://tex.z-dn.net/?f=x%5E2%20%2B%20520x%20-%20320x%20-%20166400%20%3D%200)
Factorize
![x(x + 520) - 320(x + 520)= 0](https://tex.z-dn.net/?f=x%28x%20%2B%20520%29%20-%20320%28x%20%2B%20520%29%3D%200)
Factor out x + 520
![(x - 320) (x + 520)= 0](https://tex.z-dn.net/?f=%28x%20-%20320%29%20%28x%20%2B%20520%29%3D%200)
Split
![x - 320 = 0\ or\ x + 520= 0](https://tex.z-dn.net/?f=x%20-%20320%20%3D%200%5C%20or%5C%20x%20%2B%20520%3D%200)
Solve
![x = 320\ or\ x =- 520](https://tex.z-dn.net/?f=x%20%3D%20320%5C%20or%5C%20x%20%3D-%20520)
Side length must be positive;
So:
![x = 320](https://tex.z-dn.net/?f=x%20%3D%20320)