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tangare [24]
2 years ago
12

Which of the following is equivalent to 25x2+16−40x−64y2? Select two.

Mathematics
1 answer:
Marat540 [252]2 years ago
3 0

The equivalent expression to the given expression 25x²+16−40x−64y² are; (5x-4)²−64y² and (5x−4−8y)(5x+4+8y)

<h3>Difference of two squares</h3>

According to the question:

  • We are required to determine the equivalent expression.

When we try to factorise the given expression systematically; we have;

  • 25x²+16−40x−64y² = (25x²+16−40x)−64y²

By the difference of two squares concept;

  • (25x²+16−40x) = (5x-4)²

Therefore, an equivalent expression is; (5x-4)²−64y²

Similarly, (5x-4)²−64y² is the difference of two squares and can be rewritten as; (5x−4−8y)(5x+4+8y)

Hence, we have the suggested expressions as equivalent expressions.

Learn more about equivalent expression:

brainly.com/question/2972832

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3 years ago
A very large batch of parts (assume a normal distrbution0 from a manufacturer has a mean weight = 43g and a standard deviation =
AVprozaik [17]

Answer:

5.44% probability that exactly 8 of the 16 parts you selected will have weights exceeding 45g

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Binomial probability distribution:

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

Percentage of parts with weights exceeding 45g?

1 subtracted by the pvalue of Z when X = 45. So

We have \mu = 43, \sigma = 4

Z = \frac{X - \mu}{\sigma}

Z = \frac{45 - 43}{4}

Z = 0.5

Z = 0.5 has a pvalue of 0.6915

1 - 0.6915 = 0.3075

If you slect 16 parts at random form that batch, what is the probability that exactly 8 of the 16 parts you selected will have weights exceeding 45g?

This is P(X = 8) when n = 16, p = 0.3075. So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 8) = C_{16,8}.(0.3075)^{8}.(0.6915)^{8} = 0.0544

5.44% probability that exactly 8 of the 16 parts you selected will have weights exceeding 45g

4 0
3 years ago
sphere and a cylinder have the same radius and height. The volume of the cylinder is 54 meters cubed. Amie found the volume of t
Fiesta28 [93]

Answer:

Amie should have multiplied 54 by 2/3

Step-by-step explanation:

The formula of the volume of a sphere is given by

\frac{4}{3}\pi r^3, where r is the radius of the sphere.

to find the volume of the sphere, we must find r^3

We know that the formula of a cylinder of height h and radius r is given by

\pi r^2h

So 54 = \pi r^2 h

We know that the sphere and the cylinder have the same height. Recall that the height of the sphere of radius r, is the diameter of a circle that passes through the heighest and lowest points of the sphere. Then, h=2r. This means that

54 = 2\pi r^3

From here, we know that \pi r^3 = \frac{54}{2}.

So the volume of the sphere is \frac{4}{3}\frac{54}{2} = \frac{2}{3}\cdot54.

So Amie should have multiplied 54 by 2/3.

4 0
4 years ago
Read 2 more answers
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Please help. I am trying to solve for x and i can't remember how.
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(2 - 6) (1 - 2) An then x the variable. - NOT THE ANSWER

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