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3 years ago

What time does noon start at

Mathematics

2 answers:

Gwar [14]3 years ago

7 0

Right at 12:00 is when the evening starts

maksim [4K]3 years ago

6 0

12:00 PM is noon.
12:00 AM is midnight

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Find the slope of the line that passes through (5,4) and (-4,3

stiks02 [169]

Slope= Rise over Run.

Rise= 1
Run= 7

1 divided by 7= 7

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4 years ago

Explain why it makes sense for this situation to have a linear equation

IgorC [24]

Answer:

The line of best fit for your specific question is a linear equation.

Step-by-step explanation:

A linear equation has a constant rate of growth/decline and the growth/decline rate will never change in an linear equation.

If you draw a line that approximately splits between all the data plots, you will notice the line you drew is very close to the data points.

If the data plots was a quadratic, it would be very hard to draw a line of best fit.

Linear equations can easily be identified in a graph because it is a straight line.

Perhaps insert this equation into your graphing calculator or other graphing software online (like Desmos): y = 3x+2

A quadratic equation can also easily be identified in a graph because, in most cases, it looks like a U.

Take these examples: y = $3x^2+5x+2$ or y= $-2x^2+10x+30$

3 0

3 years ago

Help me plz<br> 9.7 +-7.3=?

Bezzdna [24]

Answer:

2.4

Step-by-step explanation:

5 0

3 years ago

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SOMEBODY PLEASE HELP QUICK!!! WILL GIVE BRAINLIEST

Anna71 [15]

Carlos is correct

Since we don't know the length of sides PR and XZ, the triangles can't be congruent by the SSS theorem or the SAS theorem, and since we don't know the measure of angles Y and Q, the triangles can't be congruent by the ASA theorem, the SAS theorem or the AAS theorem. Therefore, Carlos is correct.

Carlos is correct. Since the angles P and X are not included between PQ and RQ and XY and YZ, the SAS postulate cannot be used, since it states that the angle must be included between the sides. Unlike with ASA, where there is the AAS theorem for non-included sides, there is not SSA theorem for non-included angles, so the triangles cannot be proven to be congruent.

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3 years ago

The floor of a shed given on the right has an area of 85 square feet. The floor is in the shape of a rectangle whose length is 7

lesya692 [45]

Answer: Length = 10 feet and width = 8.5 feet.

Step-by-step explanation:

Let x be the width of the floor.

Then length of the floor = $2x-7$

Given : The area of the floor = 85 square feet

We know that the area of a rectangle is given by :-

$A=l\times w$

$\Rightarrow\ 85=(2x-7)\times x\\\\\Rightarrow\ 2x^2-7x-85=0\\\\\ x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}\\\\\Rightarrow\ x=\dfrac{7\pm\sqrt{49-4(2)(-85)}}{4}\\\\\Rightarrow\ x=\dfrac{7\pm27}{4}\\\\\Rightarrow\ x=\dfrac{17}{2}, -5$

But dimension cannot be negative

So, the width of the floor = $x=\dfrac{17}{2}=8.5\text{ feet}$

And the length of the floor = $2(8.5)-7=10\text{ feet}$

6 0

4 years ago

Read 2 more answers