Answer:
The last one
Step-by-step explanation:
Because 0 < -2 -2, 0 <-4. It is not a true statement. It tell you that the middle one is wrong. The first one is wrong to because there are no equal sign.
A combination is an unordered arrangement of r distinct objects in a set of n objects. To find the number of permutations, we use the following equation:
n!/((n-r)!r!)
In this case, there could be 0, 1, 2, 3, 4, or all 5 cards discarded. There is only one possible combination each for 0 or 5 cards being discarded (either none of them or all of them). We will be the above equation to find the number of combination s for 1, 2, 3, and 4 discarded cards.
5!/((5-1)!1!) = 5!/(4!*1!) = (5*4*3*2*1)/(4*3*2*1*1) = 5
5!/((5-2)!2!) = 5!/(3!2!) = (5*4*3*2*1)/(3*2*1*2*1) = 10
5!/((5-3)!3!) = 5!/(2!3!) = (5*4*3*2*1)/(2*1*3*2*1) = 10
5!/((5-4)!4!) = 5!/(1!4!) = (5*4*3*2*1)/(1*4*3*2*1) = 5
Notice that discarding 1 or discarding 4 have the same number of combinations, as do discarding 2 or 3. This is being they are inverses of each other. That is, if we discard 2 cards there will be 3 left, or if we discard 3 there will be 2 left.
Now we add together the combinations
1 + 5 + 10 + 10 + 5 + 1 = 32 choices combinations to discard.
The answer is 32.
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Note: There is also an equation for permutations which is:
n!/(n-r)!
Notice it is very similar to combinations. The only difference is that a permutation is an ORDERED arrangement while a combination is UNORDERED.
We used combinations rather than permutations because the order of the cards does not matter in this case. For example, we could discard the ace of spades followed by the jack of diamonds, or we could discard the jack or diamonds followed by the ace of spades. These two instances are the same combination of cards but a different permutation. We do not care about the order.
I hope this helps! If you have any questions, let me know :)
Given:
Total number of colored pencils = 16
Colored pencils fit in a box = 8
To find:
The number of boxed that will fit the 16 pencils.
Solution:
According to the question 8 colored pencils will fit in a box. So, we have
8 pencils = 1 box
Multiply both sides by 2.
2×8 pencils = 2×1 box
16 pencils = 2 box
Therefore, 2 boxes are required to fit the 16 colored pencils.
The direct variation equation is y =kx
Lets see:-
4y/4 = x/4
y = 1/4x
<span>Answer: Yes, this is a direct variation </span>
Answer:
<em>40%</em>
Step-by-step explanation: <em>2 divided by 5 is 0.4 so that is 40%</em>
