Answer:
4
Step-by-step explanation:
-y₁ + y₂\-x₁ + x₂ = m
1 + 15\1 + 3 = 4
16 4
I am joyous to assist you anytime.
it would be a
Step-by-step explanation:
it would be a because you would have to subtract it
Answer:
The correct opion is;
7 ≤ p
Step-by-step explanation:
The number of signatures Devin needs to collect = 1,000 signatures
The numer of signatures Devin has already = 380 signatures
The number ofsignatures each petition page can hold = 80 signatures
Therefore;
The number of extra signatures required = 1,000 - 380 = 680 signatures
The number of petition pages required = 1,000 petitions /(80 signatures/page) = 12.5 pages
The number of pages already filled = 380 petitions /(80 signatures/page) = 4.75 pages
The number of pages remaining, p = 12.5 - 4.75 = 7.75 pages
Therefore, 7 ≤ p.
Answer: Number of College Faculty The number of faculty listed for a variety of private colleges which offer only bachelor’s degrees is listed below. Use these data to construct a frequency distribution with 7 classes, a histogram, a frequency polygon, and an ogive. Discuss the shape of this distribution. What proportion of schools have 180 or more faculty? 165 221 218 206 138 135 224 204 70 210 207 154 155 82 120 116 176 162 225 214 93 389 77 135 221 161 128 310 Source
Step-by-step explanation:
(a)
Using the definition given from the problem
![f(A) = \{x^2 \, : \, x \in [0,2]\} = [0,4]\\f(B) = \{x^2 \, : \, x \in [1,4]\} = [1,16]\\f(A) \cap f(B) = [1,4] = f(A \cap B)\\](https://tex.z-dn.net/?f=f%28A%29%20%3D%20%5C%7Bx%5E2%20%20%5C%2C%20%3A%20%5C%2C%20x%20%5Cin%20%5B0%2C2%5D%5C%7D%20%3D%20%5B0%2C4%5D%5C%5Cf%28B%29%20%3D%20%5C%7Bx%5E2%20%20%5C%2C%20%3A%20%5C%2C%20x%20%5Cin%20%5B1%2C4%5D%5C%7D%20%3D%20%5B1%2C16%5D%5C%5Cf%28A%29%20%5Ccap%20f%28B%29%20%3D%20%5B1%2C4%5D%20%20%3D%20f%28A%20%5Ccap%20B%29%5C%5C)
Therefore it is true for intersection. Now for union, we have that
![A \cup B = [0,4]\\f(A\cup B ) = [0,16]\\f(A) = [0,4]\\f(B)= [1,16]\\f(A) \cup f(B) = [0,16]](https://tex.z-dn.net/?f=A%20%5Ccup%20B%20%3D%20%5B0%2C4%5D%5C%5Cf%28A%5Ccup%20B%20%29%20%3D%20%5B0%2C16%5D%5C%5Cf%28A%29%20%3D%20%5B0%2C4%5D%5C%5Cf%28B%29%3D%20%5B1%2C16%5D%5C%5Cf%28A%29%20%5Ccup%20f%28B%29%20%3D%20%5B0%2C16%5D)
Therefore, for this case, it would be true that 
.
(b)
1 is not a set.
(c)
To begin with
Therefore
Now, given an element of 
it will belong to both sets, therefore it also belongs to 
, and you would have that
, therefore 
.
(d)
To begin with 
, therefore
