Whole numbers are positive numbers without decimals. First, list all the whole number factors of 36:
1 and 36
2 and 18
3 and 12
4 and 9
6 and 6
Next, see which one of those pairs has the highest sum:
1+36=37
2+18=20
3+12=15
4+9=13
6+6=12
The greatest possible sum the numbers can have is 37.
Hope this helps!!
Answer:
Rate = 1.125
New Value = 312,750
Step-by-step explanation:
A. 1/8 = 0.125
1+0.125=1.125
1.125 x Old value = New Value
B.
1.125 x 278,000 = New Value
312,750
Answer:
0.362
Step-by-step explanation:
When drawing randomly from the 1st and 2nd urn, 4 case scenarios may happen:
- Red ball is drawn from the 1st urn with a probability of 9/10, red ball is drawn from the 2st urn with a probability of 1/6. The probability of this case to happen is (9/10)*(1/6) = 9/60 = 3/20 or 0.15. The probability that a ball drawn randomly from the third urn is blue given this scenario is (1 blue + 5 blue)/(8 red + 1 blue + 5 blue) = 6/14 = 3/7.
- Red ball is drawn from the 1st urn with a probability of 9/10, blue ball is drawn from the 2nd urn with a probability of 5/6. The probability of this event to happen is (9/10)*(5/6) = 45/60 = 3/4 or 0.75. The probability that a ball drawn randomly from the third urn is blue given this scenario is (1 blue + 4 blue)/(8 red + 1 blue + 1 red + 4 blue) = 5/14
- Blue ball is drawn from the 1st urn with a probability of 1/10, blue ball is drawn from the 2nd urn with a probability of 5/6. The probability of this event to happen is (1/10)*(5/6) = 5/60 = 1/12. The probability that a ball drawn randomly from the third urn is blue given this scenario is (4 blue)/(9 red + 1 red + 4 blue) = 4/14 = 2/7
- Blue ball is drawn from the 1st urn with a probability of 1/10, red ball is drawn from the 2st urn with a probability of 1/6. The probability of this event to happen is (1/10)*(1/6) = 1/60. The probability that a ball drawn randomly from the third urn is blue given this scenario is (5 blue)/(9 red + 5 blue) = 5/14.
Overall, the total probability that a ball drawn randomly from the third urn is blue is the sum of product of each scenario to happen with their respective given probability
P = 0.15(3/7) + 0.75(5/14) + (1/12)*(2/7) + (1/60)*(5/14) = 0.362
Answer:
The answers is "
Option B".
Step-by-step explanation:
Where,
predicted value of lead content when traffic flow is 15.
Calculating thet-critical value
The lower predicted value 
When 
of CI use as the expected lead content:
From the given equation above, F = ma, acceleration may be calculated by slightly modifying the equation into a = F / m. Substituting the known values for force and mass,
a = 2,050,000 N / 40,000 kg = 51.25 m/s²
Thus, the acceleration achieved is 51.25 m/s².
