Answer:
23
Step-by-step explanation:
Here is the complete question
Find the volume of the parallelepiped with one vertex at the origin and adjacent vertices at (1, 0, -3), (1, 2, 4), and (5, 1, 0).
Solution
We find the volume of the parallelepiped by making a 3 × 3 column matrix whose columns are the corresponding coordinates of the vertices of the parallelepiped.
So, (1, 0, -3), (1, 2, 4) and (5, 1, 0)
![A = \left[\begin{array}{ccc}1&1&5\\0&2&1\\-3&4&0\end{array}\right]](https://tex.z-dn.net/?f=A%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%261%265%5C%5C0%262%261%5C%5C-3%264%260%5Cend%7Barray%7D%5Cright%5D)
The determinant of A is the volume of the parallelepiped. So,
detA = 1(2 × 0 - 4 × 1) - 1(0 × 0 - (-3) × 1) + 5(0 × 4 - (-3) × 2)
= 1(0 - 4) - 1(0 + 3) + 5(0 + 6)
= 1(-4) - 1(3) + 5(6)
= -4 - 3 + 30
= 23
So the volume of the parallelepiped is 23