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Lelu [443]
2 years ago
10

F(x) = 3x + 2 What is f(5)?

Mathematics
2 answers:
balu736 [363]2 years ago
5 0

Answer:

17

Step-by-step explanation:

→ f(x) = 3x + 2

→ f(5) = 3(5) + 2

→ 15 + 2

→ 17 is the answer.

elena55 [62]2 years ago
4 0

Answer:

F(5) = 17

Step-by-step explanation:

to solve, we just need to plug all values of x into 5 as shown

<em>f(x) = 3x + 2</em><em>
</em><em>f(5) = (3*5) + 2</em>

then following the format of PEMDAS (explained at footer) we solve the new equation

<em>f(5) = (3*5) + 2</em><em>
</em><em>f(5) = 15 + 2</em><em>
</em><em>f(5) = 17</em>

therefor F(5) is equal to 17

The PEMDAS format of solving equations:

the term Pemdas stands for the steps involved in solving an equation
Parenthasis (follow PEMDAS within these ( ) first untill in simplest form)
Exponents (such as x^y)
Multiply (any multiplication)
Devide (any devision)
Addition (any addition)
Subtraction (any subtraction)

hpe all this helps you ^^

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Which expression is equivalent to the one in the picture?
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Answer:

d.

Step-by-step explanation:

To convert a root to a fraction in the exponent, remember this rule:

\sqrt[n]{a^{m}}=a^{\frac{m}{n}}

The index becomes the denominator in the fraction. (The index is the little number in front of the root, "n".) The original exponent remains in the numerator.

In this question, the index is 4.

The index is applied to every base in the equation under the root. The bases are 16, 'x' and 'y'.

\sqrt[4]{16x^{15}y^{17}} = (\sqrt[4]{16})(\sqrt[4]{x^{15}})(\sqrt[4]{y^{17}}) = (2)(x^{\frac{15}{4}}})(y^{\frac{17}{4}}) = 2x^{\frac{15}{4}}}y^{\frac{17}{4}}

To find the quad root of 16, input this into your calculator. Since 2⁴ = 16, \sqrt[4]{16} = 2.

For the "x" and "y" bases, use the rule for converting roots to exponent fractions. The index, 4, becomes the denominator in each fraction.

2x^{\frac{15}{4}}y^{\frac{17}{4}}

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Determine whether the function shown in the graph is even or odd.
erica [24]

Answer:

Option A) The function is even because it is symmetric with respect to the y-axis.

Step-by-step explanation:

We are given a graph of the function.

We can see that the given function is symmetric around the y axis as the y axis acts as a mirror.

Symmetry around y-axis

  • The y-axis acts as the line of symmetry for the given graph.
  • A graph is said to be symmetric about the  y axis if (a,b) is on the graph, then we can find the point (-a,b) on the graph as well.

Even Function:

  • A function is said to be even if

f(x) = f(-x)

  • A function f is even if the graph of f is symmetric with respect to the y-axis

Odd function:

  • A function is said to be odd if

-f(x) = f(-x)

  • A function f is even if the graph of f is symmetric with respect to the x-axis.

Thus, we can write that the given function is an even function as the the graph is symmetric to the y-axis.

Option A) The function is even because it is symmetric with respect to the y-axis.

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4 years ago
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