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3 years ago

Solve the literal equation 6/p=x+a for p

Mathematics

1 answer:

Tcecarenko [31]3 years ago

8 0

It's p = 6/(x+a).

Multiply both sides by p to get 6 = p(x+a), then divide both sides by (x+a) to get 6/(x+a) = p.

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Divide each of the following numbers by 10. a. 9.48 b. .6 c. 84.5 d. .0024 e. .3678 f. 25

DedPeter [7]

Answer:

1.) 0.948

2.)0.06

3.)8.45

4.).00024

5.)0.03678

6.)2.5

Hope this helps you some!!

6 0

3 years ago

Read 2 more answers

.In the coordinate x,y the point x is calledorigin abscissa line y-axis

Dmitry [639]

Answer:

The x coordinate is known as abscissa (B)

Step-by-step Explanation:

In a Cartesian plane, we learn many such terms which represent a point, or a line, or cooridnates of some points etc $.$

Such terms are:

Origin (Intersection of x axis and y-axis.)
x - axis (Horizontal line)
y - axis (Vertical line)
abscisaa (x -coordinate)
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5 0

2 years ago

Find the distance between points P(5, 1) and Q(3, 4) to the nearest tenth

pav-90 [236]

Answer:

$\sqrt{13}$ units

Step-by-step explanation:

The distance formula is $d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$ where $d$ is the distance between points $(x_1,y_1)$ and $(x_2,y_2)$ . Let $(x_1,y_1)\rightarrow(5,1)$ and $(x_2,y_2)\rightarrow(3,4)$ , thus:

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\\\\d=\sqrt{(3-5)^2+(4-1)^2}\\\\d=\sqrt{(-2)^2+(3)^2}\\\\d=\sqrt{4+9}\\\\d=\sqrt{13}$

Therefore, the distance between points P(5,1) and Q(3,4) is $\sqrt{13}$ units.

8 0

2 years ago

Please help what is x(5x6)

Rom4ik [11]

It will equal
x(5)(6)=30x

3 0

3 years ago

Read 2 more answers

Which Property of real numbers does this equation show? 4 x 1 = 4

Colt1911 [192]

Answer:

This is multiplicative identity in which 4✖️1=4

Step-by-step explanation:

Hope it will help you:)

7 0

3 years ago