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mojhsa [17]
2 years ago
5

Lisa has 4 dogs. Each of the 4 dogs weighs an integer number of kg. No two of them weigh the same. Their total weight is 60 kg.

The second heaviest dog weighs 28 kg. How heavy is the third heaviest dog?
Mathematics
1 answer:
Aneli [31]2 years ago
7 0

The weight of the third heaviest among the four dogs is 2 kg.

<h3>What is an equation?</h3>

An equation is an expression that shows the relationship between two or more numbers and variables.

The 4 dogs weight is 60 kg with each dog weight been different. The second heaviest dog weighs 28 kg.

Let the heaviest dog be 29 kg, the third heaviest be 2 kg and the fourth be 1 kg.

29 + 28 + 2 + 1 = 60 kg

The weight of the third heaviest among the four dogs is 2 kg.

Find out more on equation at: brainly.com/question/2972832

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Sam and Jeremy have ages that are consecutive odd integers. The product of their ages is 783, which equation could be used to fi
stepladder [879]
(2x+1)=Jeremy´s age
(2x+3)=Sam´s age.
we suggest this equation:
(2x+1)(2x+3)=783
4x²+6x+2x+3=783
4x²+8x-780=0
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We solve this quadratic equation:
x=[-2⁺₋√(4-4*1*(-195))]/2=(-2⁺₋28)/2

x₁=(-2-28)/2=-15 this solution is not valid.
x₂=(-2+28)/2=13

Jeremy´s age=2x+1=2*13+1=27
Sam´s age=2x+3=2*13+3=29



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