Question

Find the distance round to the nearest tenth (-8, -6) (-3,-2)​

Answer 1

Answer:

$\displaystyle d \approx 6.4$

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

1. Brackets
2. Parenthesis
3. Exponents
4. Multiplication
5. Division
6. Addition
7. Subtraction

• Left to Right

Algebra I

• Coordinates (x, y)

Algebra II

• Distance Formula: $\displaystyle d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Step-by-step explanation:

Step 1: Define

Point (-8, -6)

Point (-3, -2)

Step 2: Find distance d

Simply plug in the 2 coordinates into the distance formula to find distance d

1. Substitute in points [Distance Formula]:                                                   $\displaystyle d = \sqrt{(-3+8)^2+(-2+6)^2}$
2. [√Radical] (Parenthesis) Add:                                                                        $\displaystyle d = \sqrt{(5)^2+(4)^2}$
3. [√Radical] Evaluate exponents:                                                                    $\displaystyle d = \sqrt{25+16}$
4. [√Radical] Add:                                                                                              $\displaystyle d = \sqrt{41}$
5. [√Radical] Evaluate:                                                                                        $\displaystyle d = 6.40312$
6. Round:                                                                                                            $\displaystyle d \approx 6.4$

Answer 2

Answer:

6.4

Step-by-step explanation:

d=√((−3−(−8))^2+(−2−(−6))^2)

d=√((5)^2+(4)^2)

d=√(25+16)

d=√(41)

d=6.403124

d=6.4