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vesna_86 [32]
3 years ago
9

I have 10tens n 2 tens what is the answer

Mathematics
1 answer:
Alchen [17]3 years ago
6 0
Is the n and if so then it is either 200 or 120
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9x + 26 + 7x - 17 = 2x + (-3x) + 5x
slega [8]
9x + 26 + 7x - 17 = 2x + (-3x) + 5x =
16x + 9 = 2x - 3x + 5x =
16x + 9 = 4x
9 = 4x - 16x
9 = - 12x
-9/12 = x
- 3/4 = x
4 0
3 years ago
-2x-5y=3 3x-8=-6 solve by substition
ELEN [110]
Maybe use photo math i guess
6 0
3 years ago
Read 2 more answers
Please help!! thank you.
Zina [86]

(A) Product of -2x^{3}+x-5 and x^{3}-3x-4 is:

(-2x^{3}+x-5)(x^{3}-3x-4)

=-2x^{3}(x^{3}-3x-4)+x(x^{3}-3x-4)-5(x^{3}-3x-4)

=(-2x^{3})(x^{3})+(-2x^{3})(-3x)+(-2x^{3})(-4)+x(x^{3})+(x)(-3x)+(x)(-4)+(-5)(x^{3})+(-5)(-3x)+(-5)(-4)

=-2x^{6}+6x^{4}+8x^{3}+x^{4}-3x^{2}-4x-5x^{3}+15x+20

=-2x^{6}+6x^{4}+x^{4}+ 8x^{3}-5x^{3}-3x^{2}-4x+15x+20

=-2x^{6}+7x^{4}+3x^{3}-3x^{2}+11x+20

(B) Yes.

Product of -2x^{3}+x-5 and x^{3}-3x-4 = Product of x^{3}-3x-4 and -2x^{3}+x-5 because multiplication is commutative.

Commutative Property of multiplication says that a.b = b.a.

Thus, multiplication is same irrespective of the order of two numbers.



5 0
4 years ago
Solve each equation by completing the square 2q^2+8q=3
3241004551 [841]

Answer:

Divide by 2

q^2+4q=3/2

q^2+4q(4/2)^2=3/2+(4/2)^2

(q+4/2)^2=3/2+16/4

taking the square root of both side

√(q+4/2)^2=√(3/2+16/4)

Note that the square will cancel the square root then you will take LCM on the right hand side

q+4/2=√6+16/4

q+4/2=√22/4

q= -4/2+-√22/4

q=(-4+_√22/4)

5 0
3 years ago
PLEASE HELP ME I AM DESPERATE
Paladinen [302]

Answer: B 5+5=10+4+4+4=12+3 10+12+3 25 lol

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
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