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alexira [117]
2 years ago
10

Help me plsss i need to do it fast 12 min left help me pls

Mathematics
2 answers:
Simora [160]2 years ago
7 0

Answer:

$44

Step-by-step explanation:

She has 79 AFTER her grandfather gave her 35. So you would subtract 35 from the 75 and get $44

ser-zykov [4K]2 years ago
7 0

Answer:

you're correct it's 44 you do 79 - 35 and you get 44

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Pls help
BlackZzzverrR [31]

Answer:

y =  8 \:  \:  \: x =  - 10

Step-by-step explanation:

4( - 6x - 9y =  - 12) \\ 3(8x + 9y =  - 8) \\  \:  \:  \:  \:  \:  \:  \\  - 24x - 36y =  - 48 \\ 24x + 27y =  - 24 \\  \\  - 9y =  - 72 \\ y = 8 \\  \\  \\  \\  \\  - 6x  -  9y=  - 12 \\  - 6x  -  72 = -  12 \\  - 6x =  - 12 + 72 \\  - 6x = 60 \\ x =  - 10

8 0
2 years ago
4<br> Write an exponential decay<br> equation with a rate of 25% and<br> an initial value of 6.
3241004551 [841]
Sorry I dont no hala da yazıyor ben ne oldu sana böyle
3 0
3 years ago
I need to find the sum of this equation please help :)
hoa [83]

Answer:

i think

-17x^2 +3x

.....

4 0
3 years ago
Answer the question below. Be sure to show your work
likoan [24]

ANSWER:

We have to find new side-lengths of PQR triangle.

Original sides are.

\begin{gathered} PQ\text{ = 8cm} \\ QR=17\operatorname{cm} \\ RP=15\operatorname{cm} \end{gathered}

After multiplying by 2.5 we get

\begin{gathered} PQ^{\prime}=2.5\times PQ=(8\times2.5)cm=20\operatorname{cm} \\ QR^{\prime}=(17\times2.5)cm=42.5\operatorname{cm} \\ RP^{\prime}=(15\times2.5)cm=37.5\operatorname{cm} \end{gathered}

These are the new sides of the P'Q'R' triangle.

5 0
1 year ago
Pleaseeee help w these math questions! please show work!!!<br><br> 50 points
Schach [20]

9. You need an exact answer. So I will give you it but I'll also give you an approximation because it might help you understand it more.

Because we know the cosine fo theta, we can evaluate the inverse cosine of -2/3 first to find theta.

sin^{-1}(-2/3) = 131.81° approx.

Because 131.81° is in the second quadrant its third quadrant partner is 228.19°. Which would make the sine 0.75 approximately.

But we need an exact answer I suppose so which is this disgusting mess...sin(2\pi -cos^{-1}(\frac{-2}{3})). I know it looks scary but it is basically  all the steps we just did but without evaluating anything.

This can be simplified using: sin(x− y) = sinxcosy−cosxsiny

To... -sin(cos^{-1}(\frac{-2}{3}))

answer: -sin(cos^{-1}(\frac{-2}{3}))

10. Okay. So because we have a point we can say that...

θ = tan^{-1}(-9/11)

sin(θ) = +sin(tan^{-1}(-9/11))

11. arcsin(-0.37) = sin^{-1}(-0.37) = -21.72°+2kπ or 201.72°+2kπ approx. where k has to be an integer

answer: idk if you want one or more solutions so I gave you them all.

12. arccos(-√3/2) = cos^{-1}(\frac{-\sqrt{3} }{2}) = \frac{5\pi }{6}+2k\pi, \frac{7\pi }{6}+2k\pi

Remember that "k" must be an integer.

answer: 5π/6

6 0
3 years ago
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