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3 years ago

3kx+24=9kx solve for x

1 answer:

3 0

To solve this, first subtract 3kx from both sides so that both the x variables are on the same side. This will result in: 24=9kx-3kx.
Since 9kx and -3kx are like terms, they will combine and you will get 24=6kx
Now, divide 6k from both sides to isolate x and you get x=24/6k.
However, you notice that 24 and 6k both have a common factor which is 6, so you simplify 24/6k to 4/k which gives you your answer of x=4/k

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Gayle starts to save at age 20 for an extended vacation around the world that she will take on her 45th birthday. She will contr

Katen [24]

For this case we have the following equation:
P (t) = P (1 + r / n) ^ (n * t)
Where,
P: initial investment
r: interest
n: periods
t: time
she will take on her 45th birthday:
for t = 25:
P (25) = 1000 * (1 + 0.0165 / 4) ^ (4 * 25)
P (25) = 1509.31 $
Answer:
The future value of this investment when she takes her trip is:
P (25) = 1509.31 $

8 0

2 years ago

Read 2 more answers

The diagram shows a right-angled triangle.

goldfiish [28.3K]

Answer:

Step-by-step explanation:

Ac²= AB²+ BC²

Ac²= 4²+15²= 16+225

Square both side

Ac = √241= 15.52cm

8 0

2 years ago

Andre rode his bike at a constant speed. He rode 1 mile in 5 minutes. Which of these equations represents the amount of time t (

Alex

Answer:

.20 per minute.If you dives 1 mile by 5 min u will get .20

4 0

2 years ago

3/4 minus 1/8 in simplest form

mash [69]

.625 or if you want it in a fraction it is 625/1000

6 0

2 years ago

Find the ordered pair that makes both the equations below true

NNADVOKAT [17]

Answer:

(3, 1)

Step-by-step explanation:

(a) Algebraic solution

(1) y = -⅔x + 3

(2) y = 2x - 5

Set Equation (1) equal to Equation (2)

-⅔x + 3 = 2x - 5

Multiply each side by 3

-2x + 9 = 6x - 15

Add 15 to each side

-2x + 24 = 6x

Add 2x to each side

24 = 8x

Divide each side by 3

(3) x = 3

Substitute (3) into (2)

y = 2×3 - 5 = 6 - 5 = 1

The ordered pair that makes both equations true is (3, 1).

(b) Graphical solution

In the diagram below, the red line is the graph of Equation (1). The blue line is the graph of Equation (2). The point of intersection is at (3, 1).

7 0

3 years ago