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3 years ago

3kx+24=9kx solve for x

1 answer:

3 0

To solve this, first subtract 3kx from both sides so that both the x variables are on the same side. This will result in: 24=9kx-3kx.
Since 9kx and -3kx are like terms, they will combine and you will get 24=6kx
Now, divide 6k from both sides to isolate x and you get x=24/6k.
However, you notice that 24 and 6k both have a common factor which is 6, so you simplify 24/6k to 4/k which gives you your answer of x=4/k

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astra-53 [7]

Answer:

1. 44 + 3x

2. 2y - 8

3. x - 6

15. $5\frac{7}{8}$

16. $6\frac{1}{3}$

17. $3\frac{7}{9}$

Step-by-step explanation:

1. 7² + 2² - 5 - 4 + 3x

49 + 4 - 5 - 4 + 3x

53 - 5 - 4 + 3x

48 - 4 + 3x

44 + 3x

2. - y - 5 + y + 2(2y-y) - 3

-y - 5 + y + 4y - 2y -3

-y - 5 + 5y - 2y - 3

4y - 2y - 5 - 3

2y - 8

3. 5x -3 - x - 3(x + 1²)

5x - 3 - x - 3x - 3

4x - 3x - 3 -3

x - 3 -3

x - 6

15. $7\frac{1}{4} - 1\frac{3}{8}$

= $7 \frac{2}{8} - 1\frac{3}{8}$

= $\frac{58}{8} - \frac{11}{8}$

= $\frac{47}{8}$ → $5\frac{7}{8}$

16. $9 - 2\frac{2}{3}$

= $\frac{54}{6} - 2\frac{4}{6}$

= $\frac{54}{6} - \frac{16}{6}$

= $\frac{38}{6}$ → $6\frac{2}{6}$ → $6\frac{1}{3}$

17. $10\frac{1}{3} - 6\frac{5}{9}$

= $10 \frac{3}{9} - 6\frac{5}{9}$

= $\frac{93}{9} - \frac{59}{9}$

= $\frac{34}{9}$ → $3\frac{7}{9}$

Hope this helps.

6 0

3 years ago

How do I solve question 5?

Nezavi [6.7K]

A) x^2 + y^2 = 80
B) x * y = 12

What is x^2 -y^2?
B) x * y = 12
So y = 12 / x
A) x^2 + (12/x)^2 = 80
x^2 + (12/x)^2 = 80
x^2 + (144/x^2) = 80
Multiplying each side by x^2
x^4 + 144 = 80x^2
x^4 -80x^2 + 144 = 0
X = 1.355 (found by trial and error)
Y = 8.85608 (found by trial and error)

3 0

3 years ago