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2 years ago

Estimate the difference of 621 - 267 by rounding to the nearest hundred.

2 answers:

6 0

I have found the answer by going to the nearest hundred and making 600 and the I rounded 267 up because it is five or more so it will be rounded to 300 and then you subtract 600-300 and the answer will be 300

dimulka [17.4K]2 years ago

5 0

Answer:

300

Step-by-step explanation:

621 rounds to 600 because 21 is smaller than 50. 267 round to 300 since 67 is bigger than 50.

600-300=300

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Need the awnser for 3

Sidana [21]

Answer:

here u go

Step-by-step explanation:

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5 0

2 years ago

Which pair is made up of prime numbers 11 & 33 , 42 & 56 , 37 & 67, 57 & 97

Cerrena [4.2K]

Answer:

37 & 67

Step-by-step explanation:

11 & 33

11 - 1, 11

11 is prime

33 - 1, 3, 11, 33

33 is composite number

11 & 33 is incorrect

42 & 56

42 - 1, 2, 3, 6, 7, 14, 21, 42
56 - 1, 2, 4, 7, 8, 14, 28, 56
Both 42 and 56 are composite numbers
42 & 56 is incorrect

37 & 67

37 - 1, 37
67 - 1, 67
Both 37 and 67 are prime numbers
37 & 56 is correct

57 & 97

57 - 1, 3, 19, 57
97 - 1, 97
57 is a composite number, 97 is a prime number
57 & 97 is incorrect

3 0

3 years ago

(A) How many ways are there to distribute seven identical apples and six identical pears to three distinct people such that each

sergejj [24]

Answer:

Step-by-step explanation:

ကိနဩန္ကိကိကိဩနဩတိ္ကိနဩန္ကိကိကိဩနဩတပဃဂ

3 0

3 years ago

If CD=18, find the value of EB.

aliina [53]

Step-by-step explanation:

Chord AB and Chord CD are equidistant from the center of the circle.

$\therefore \: chord \: AB \cong chord \: CD \\ \\ \therefore \: \frac{1}{2} \: \: AB \cong \frac{1}{2} \: \: CD \\ \\ \therefore \: EB = \frac{1}{2} \: \times 18\\ \\ \huge \purple{ \boxed{\therefore \: EB =9}}$

5 0

3 years ago

You take a quiz with 6 multiple choice questions. After you studied your estimated that you would have about an 80 % chance of g

Arada [10]

Answer:

1.15%

Step-by-step explanation:

To get the probability of m independent events you multiply the individual probability of each event. In this case we have m independent events, each one with the same probability, therefore:

$p^{m}$

$0.8^{20} = 1.15\%$

This is a particlar scenario of binomial distribution problem. So the binomial distribution questions are about the number of success of m independent events, where every individual event has the same p probability. In the question we have 20 events and each event has a probability of 80%. The binomial distribution formula is:

$\binom{n}{k} * p^{k} * (1-p)^{n-k}$

n is the number of events

k is the number of success

p is the probability of each individual event

$\binom{n}{k}$ is the binomial coefficient

the binomial coefficient allows to find the subsets of k elements in a set of n elements. In this case there is only one subset possible since the only way to get 20 of 20 correct questions is to getting right all questions (for getting 19 of 20 questions there are many ways, for example getting the first question wrong and all the other questions right, or getting second questions wrong and all the other questions right, etc).

$\binom{n}{k} = \frac{n!}{k!(n-k)!}$

therefore, for this questions we have:

$\frac{20!}{20!(20-20)!} * 0.8^{20} * (1-0.8)^{0} = 1.15\%$

4 0

3 years ago