To determine the total charge of the protons in the gas, we need to know the number of protons that are present. We use Avogadro's number to know such value. We do as follows:
2.2 mol ( 6.022x10^23 protons / 1 mol ) = 1.325x10^24 protons
Total charge = 1.6021766208×10^−19 C (1.325x10^24) = 212262.77 C
Answer:
F⁻(aq) + H⁺(aq) ⇄ HF(aq)
Explanation:
When aqueous solutions of potassium fluoride and hydrochloric acid are mixed, an aqueous solution of potassium chloride and hydrofluoric acid results. The corresponding molecular equation is:
KF(aq) + HCl(aq) ⇄ KCl(aq) + HF(aq)
The full ionic equation includes all the ions and the molecular species. HF is a weak acid so it exists mainly in the molecular form.
K⁺(aq) + F⁻(aq) + H⁺(aq) + Cl⁻(aq) ⇄ K⁺(aq) + Cl⁻(aq) + HF(aq)
The net ionic equation includes only the ions that participate in the reaction (not spectator ions) and the molecular species.
F⁻(aq) + H⁺(aq) ⇄ HF(aq)
Question 1
The correct answer is a.
Explanation
The relationship between
and
is given by
, We can use
and
. In a we are given the concentration of [OH] and so we use that to find the pOH, then from pOH we can find the pH.
![pOH= -log [2.4 \times 10^-^2] = 1.62\\\\pH = 14 - 1.62= 12.38](https://tex.z-dn.net/?f=pOH%3D%20-log%20%5B2.4%20%5Ctimes%2010%5E-%5E2%5D%20%3D%201.62%5C%5C%5C%5CpH%20%3D%2014%20-%201.62%3D%2012.38)

c. HCl is a strong acid so it dissociates to 0.0001
and 0.0001
, hence
![pH= -log[0.0001] = 4](https://tex.z-dn.net/?f=pH%3D%20-log%5B0.0001%5D%20%3D%204)
![d.pOH= -log [4.4 \times 10^-9] = 8.36\\\\pH= 14- 8.36 = 5.64](https://tex.z-dn.net/?f=%20d.pOH%3D%20-log%20%5B4.4%20%5Ctimes%2010%5E-9%5D%20%3D%208.36%5C%5C%5C%5CpH%3D%2014-%208.36%20%3D%205.64)
has a pH 12.36 which is greater than 7
Question 2
The correct answer is d
.
Explanation
This is because solids and liquids do not appear in the equilibrium constant expression. Since
.
For the equation

![K= \frac{[CO_2][SO_2]}{[O_2]}](https://tex.z-dn.net/?f=K%3D%20%5Cfrac%7B%5BCO_2%5D%5BSO_2%5D%7D%7B%5BO_2%5D%7D)
Question 3
The correct answer is c
In a molecule the oxidation number are assigned to get the sum of a neutral charge or ion. The overall charge of
is -2 and in all its compounds oxygen has -2 charge, hence

Question 4
The correct answer is b. An oxidising agent must gain electrons in a reaction, thus it is the one that undergoes reduction.In order find out what is being reduced we write half reactions for molecules that change their state.
and
are spectactor ions in this reaction.

In the chloride half reaction
gains electrons to become
ions.
Question 5
The last element D is correct. When a nucleus decays by beta emission it produces a daughter nucleus that has same mass number but different atomic number. Therefore beta-decay will have equation

Question 6
The correct answer is a. A beta particle is an electron because it has a charge of -1 and has same mass as an electron, while a positron is a particle with the same mass as an electron but with a positive charge.
The answer is d. mole fraction is not affected by changes in temperature. The colligative properties is only depend on the number of the solute in the solvent.
Answer:
Do you have a picture of this?